Answer:
6.5 seconds
Step-by-step explanation:
When s=0, we have ...
0 = -16t^2 +676
t^2 = 42.25 . . . . . add 16t^2, divide by 16
t = √42.25 = 6.5
6.5 seconds will pass before the object hits the ground.
B is the only one that would not be perpendicular to the first line. The first line would have a point-slope intercept form of y=-6x+3 and so any line perpendicular to it would require a slope of 1/6. All of them have a slope of 1/6 except B, which has a slope of 6. Let me know if you need a complete show of work as I can show you the math behind my answer.
Answer:
9/32
Step-by-step explanation:
BC = black circle
BS = black square
WC = white circle
WS = white square
Given:
(WC + WS) / (BC + BS) = 5 / 11
WC / WS = 3 / 7
BC / BS = 3 / 8
Find: (BC + WC) / (BC + BS + WC + WS)
Solve for WC and BC in the last two equations, then substitute into the first:
WC = 3/7 WS
BC = 3/8 BS
WC + WS = 5/11 (BC + BS)
3/7 WS + WS = 5/11 (3/8 BS + BS)
10/7 WS = 5/8 BS
WS = 7/16 BS
Therefore:
WC = 3/7 WS
WC = 3/16 BS
Substitute:
(BC + WC) / (BC + BS + WC + WS)
(3/8 BS + 3/16 BS) / (3/8 BS + BS + 3/16 BS + 7/16 BS)
(9/16 BS) / (2 BS)
9/32
Answer:
B!
Step-by-step explanation:
we know that (x-5) and (y-6) must add up to 129 because 180-51 is 129
now let's plug in the values to see
51-5= 66 63-6 = 57
57+66 is 123, not this one, let's repeat the same step
77-5 is 72, 63-6 is 57, these added is 129
Answer:
120
Step-by-step explanation:
just do 10*12 which is 120.
