You just need to plug those expressions inside the formula: it doesn't matter if they're expressions involving a variable instead of plain numbers: the formula becomes

$V = \pi (x+8)^2(2x+3)$

If you want, you can simplify it by expanding the square and then multiply the two parenthesis:

$V = \pi (x^2+16x+64)(2x+3) = \pi (2 x^3 + 35 x^2 + 176 x + 192)$

6 0

3 years ago

Fiona and her friends went to a smoothie shop. They ordered three strawberry smoothies and two protein shakes for a total of $24

IRINA_888 [86]

I believe the answer is 5.15 .

4 0

4 years ago

Solve the following quadratic equation for all values of xx in simplest form. 3(x+1)²-15=-12

suter [353]

Answer:

x = 0, -2

Step-by-step explanation:

3 0

3 years ago