The number of passwords that would be allowed if users were allowed to reuse the letters and numbers is 30891577600
<h3>How to determine the number of passwords</h3>
The given parameters are:
Password length = 8
Letters = 6
Numbers = 2
There are 26 letters and 10 digits.
Since the letters and the numbers can be repeated, then the number of passwords is:
Count = 26^6 * 10^2
Evaluate
Count = 30891577600
Hence, the number of passwords that would be allowed if users were allowed to reuse the letters and numbers is 30891577600
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Answer:
4^12
Step-by-step explanation:
4^9 * 4^3
We know that a^b * a^c = a^ (b+c)
4^9 * 4^3
4^(9+3)
4^12
Probability is the chance of an event occuring. It is obtained by the formula number of outcomes / total number of possible outcomes.
The probability of a blue jay being the next bird papa sees is given by number of blue jays / total number of birds = 59 / (59 + 68 + 12 + 1) = 59 / 140 = 0.4214
Answer:
3) Functional
4)IS NOT Functional
Step-by-step explanation:
3) Each of the X Do not have the same Y number.
4)One of the X Numbers have the same Y number
I am sorry if I could not answer number 5 and 6.