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zhuklara [117]
2 years ago
15

A sample of students will be selected from all the students at a high school. Which of the following sampling methods is least l

ikely to produce a representative sample of the students?
From a list of all student names, randomly select 50 names from the list for the sample.
A



Randomly choose five classrooms in the school and use all the students in those classrooms for the sample.
B



Divide the students into the four class years (freshman, sophomore, junior, senior) and randomly select students from each year in proportion to the number of students in each year.
C


From a numbered list of all student names, randomly choose a starting point and then choose every tenth student on the list.
D

From a randomly chosen home basketball game, choose every tenth student who enters the gymnasium.
E
Mathematics
1 answer:
Feliz [49]2 years ago
8 0

Answer:

B seems most logical and fair

Step-by-step explanation:

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Which hyperbola has one focus point in common with the hyperbola (y+11)^2/(15^2)-(x-7)^2/(8^2)=1
irina [24]
\bf \textit{hyperbolas, vertical traverse axis }\\\\
\cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1
\qquad 
\begin{cases}
center\ ({{ h}},{{ k}})\\
vertices\ ({{ h}}, {{ k}}\pm a)
\end{cases}\\\\
-------------------------------\\\\
\cfrac{(y+11)^2}{15^2}-\cfrac{(x-7)^2}{8^2}=1\implies \cfrac{(y-(-11))^2}{15^2}-\cfrac{(x-7)^2}{8^2}=1\\\\
-------------------------------\\\\
c=\textit{distance from the center to either foci}\\\\
c=\sqrt{a^2+b^2}\implies c=\sqrt{15^2+8^2}\implies \boxed{c=17}

now, if you notice, the positive fraction, is the one with the "y" variable, and that simply means, the hyperbola traverse axis is over the y-axis, so it more or less looks like the picture below.

now, from the hyperbola form, we can see the center is at (7, -11), and that the "c" distance is 17.

so, from -11 over the y-axis, we move Up and Down 17 units to get the foci, which will put them at (7, -11-17) or (7, -28) and (7 , -11+17) or (7, 6)

5 0
3 years ago
Read 2 more answers
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