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sergiy2304 [10]
3 years ago
12

What is the renters rule

Mathematics
1 answer:
Leviafan [203]3 years ago
5 0
I don’t understand ???
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The ordered pairs on the graph represent a proportional relationship. What is the constant proportionality of Y to X
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A 7/4 because the slope of the line is 7/4
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The measure of a vertex angle of an isosceles triangle is 120° and the length of a leg is 8 cm. Find the length of a diameter of
Goryan [66]

ANSWER

The length of a Diameter is 3.714

EXPLANATION

The circumscribed triangle is shown in the attachment.

We use the cosine ratio to find the altitude of the isosceles triangle.

\cos(60 \degree)  =  \frac{altitude}{hypotenuse}

\cos(60 \degree)  =  \frac{altitude}{8}

Altitude =8cos(60°)

Altitude=4cm

Let the upper half of the altitude be y cm.

Then the radius of the circle is (y-4)cm

The upper radius meets the tangent at right angles.

From the smaller right triangle,

\sin(60 \degree)  =  \frac{4 - y}{y}

y\sin(60 \degree)  = 4 - y

y\sin(60 \degree)   + y= 4

(\sin(60 \degree)   + 1)y= 4

y=  \frac{4}{\sin(60 \degree)   + 1}

y = 16 - 8 \sqrt{3}

y=1.857

The diameter is 2y

d = 32 - 16 \sqrt{3}

=2(1.875)

The length of a Diameter is 3.714

7 0
3 years ago
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When a metallic ball bearing is placed inside a cylindrical container, of radius 2 cm, the height of the water, inside the conta
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It will be 1.2 cm,......
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ABC IS a right angled triangle at B and D is a point on BC. If AD=18cm , BD=9cm and CD = 4 cm, find AC
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AC = \sqrt{ AB^{2} + BC^{2} } =  \sqrt{412} = 2 \sqrt{103}
4 0
3 years ago
Is (1, 2) a solution to the inequality 6x - y> 3?
Lostsunrise [7]

Answer:

<u><em>Yes.</em></u>

Step-by-step explanation:

<em>To find the answer we will put it into the equation, since</em><em><u> x = 1 and y = 2</u></em><em> we will write it like this, </em><u><em>6(1) - 2 > 3.</em></u><em>  Since </em><u><em>6 x 1 = 6</em></u><em>, we will now </em><u><em>subtract 6 from 2 which equals 4</em></u><em>.  Therefore, the equation is </em><u><em>correct because 4 is bigger than 3.</em></u>

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3 years ago
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