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AleksAgata [21]
3 years ago
7

please i will mark as brainliest

Mathematics
1 answer:
hodyreva [135]3 years ago
6 0

Answer:

Answer: C

Step-by-step explanation:

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<img src="https://tex.z-dn.net/?f=%28-3x%5E2y%29%5E%7B4%7D" id="TexFormula1" title="(-3x^2y)^{4}" alt="(-3x^2y)^{4}" align="absm
Valentin [98]

Answer:

errr polynomials ahaha

so basically we can multiply the power outside of the parantheses with the exponents on the inside:

so

-3x^{2*4} y^{1*4}

this will give us:

-3x^8y^4

we also unfortunately, have to use the power on the coefficient -3 as well  and we cant just MULTIPLY -3 by 4, we are going to have to multiply -3 with -3 4 TIMES(anytime we see a coefficient we MUST multiply the coefficient by itself according to the number outside of the parantheses)

so:

-3*-3*-3*-3=81

final expression

81x^{8}y^{4}

5 0
3 years ago
Read 2 more answers
PLEASE help, I don’t understand this in the slightest and I’m about to snap my own neck ahaaa :((
Margarita [4]

Answer:

Calm down, it's simple. Take 180 degrees and subtract M-2 from it. (180-125: 55) A is 55. Than you can fill in A. Repeat with other angles, looking for a pair that forms 180 degrees. Take the value you know and use it to calculate the other one. Take your time.

6 0
3 years ago
Write an exponential function y = abx for a graph that includes (2, 24) and (3, 48).
labwork [276]
I think you mean y=ab^x.
First, plug in the values of x=2 and y=24 for the first equation, and x=3 and y=48 for the second one:

24 = ab^2
48 = ab^3

divide equation 2 by equation 1:
2 = b^1

or, more simply:
2 = b

now plug b into one of the equations to get "a":

24 = a*2^2
24 = a*4
6 = a

So, the answer is y = 6(2)^x
(I think you need to specify the power of x in your answers)
7 0
3 years ago
Read 2 more answers
A turtle was crawling at the rate of 43 cm per minute. How many kilometers would this turtle crawl in one day (24 hours) if it d
irga5000 [103]

Answer:

0.6192

Step-by-step explanation:

4 0
3 years ago
Find all solutions to
BARSIC [14]

Answer:

x= 0 , \frac{1}{14} , \frac{-1}{12}

Step-by-step explanation:

Given, equation is \sqrt[3]{15x-1} + \sqrt[3]{13x+1} = 4\sqrt[3]{x}. →→→ (1)

Now, by cubing the equation on both sides, we get

( \sqrt[3]{15x-1} + \sqrt[3]{13x+1} )³ = (4\sqrt[3]{x})³

⇒ (15x-1) + (13x+1) + 3×\sqrt[3]{15x-1}×\sqrt[3]{13x+1} (\sqrt[3]{15x-1} + \sqrt[3]{13x+1}) = 64 x.

⇒ 28x + 3×\sqrt[3]{15x-1}×\sqrt[3]{13x+1} (4\sqrt[3]{x}) = 64x.        

(since from (1),  \sqrt[3]{15x-1} + \sqrt[3]{13x+1} = 4\sqrt[3]{x})

⇒ 12× \sqrt[3]{15x-1}×\sqrt[3]{13x+1} (\sqrt[3]{x})= 36x.

⇒ 3x = \sqrt[3]{(15x-1)(13+1)(x)}.

Now, once again cubing on both sides, we get

(3x)³ = (\sqrt[3]{(15x-1)(13+1)(x)})³.

⇒ 27x³ = (15x-1)(13x+1)(x).

⇒ 27x³ = 195x³ + 2x² - x

⇒ 168x³ + 2x² - x = 0

⇒ x(168x² + 2x -1) = 0

⇒ by, solving the equation we get ,

x = 0 ; x = \frac{1}{14} ; x = \frac{-1}{12}

therefore, solution is x= 0 , \frac{1}{14} , \frac{-1}{12}

7 0
3 years ago
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