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3 years ago

6

BRAINLIEST AWARD TO CORRECT ANSWER A cylindrical cardboard tube is 60 cm long and open at both ends. Its surface area is 950 cm2

. Calculate its radius to the nearest tenth of a centimetre.

1 answer:

ozzi3 years ago

4 0

Take 950^2/60^2=250.69444... then take that $\pi$ =79.80087361 lastly take that/2=39.9004368

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VLD [36.1K]

It would equal 30 c cuz there is 8 fluid oz in a cup

4 0

3 years ago

Read 2 more answers

Solve. <br> X^2+5x-10=0 <br> Enter your answers, as exact values, in the boxes.

Grace [21]

Answer:

$x^{2} + 5x - 10 = 0 \\x^{2} + 5x = 10 \\ x(x + 5) = 10$

Now,

Either,

x=10

Or,

x+5=10

x=10-5

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3 years ago

T what point does the curve have maximum curvature? Y = 7ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as

Nookie1986 [14]

Formula for curvature for a well behaved curve y=f(x) is

K(x)= $\frac{|{y}''|}{[1+{y}'^2]^\frac{3}{2}}$

The given curve is y=7 $e^{x}$

${y}''=7e^{x}\\ {y}'=7e^{x}$

k(x)= $\frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}$

${k(x)}'=\frac{7(e^x)(1+49e^{2x})(49e^{2x}-\frac{1}{2})}{[1+49e^{2x}]^{3}}$

For Maxima or Minima

${k(x)}'=0$

$7(e^x)(1+49e^{2x})(98e^{2x}-1)=0$

→ $e^{x}=0∨ 1+49e^{2x}=0∨98e^{2x}-1=0$

$e^{x}=0 , ∧ 1+49e^{2x}=0$ [not possible ∵there exists no value of x satisfying these equation]

→ $98e^{2x}-1=0$

Solving this we get

x= $-\frac{1}{2}\ln{98}$

As you will evaluate ${k(x})}''$ <0 at x= $-\frac{1}{2}\ln98$

So this is the point of Maxima. we get y=7×1/√98=1/√2

(x,y)=[ $-\frac{1}{2}\ln98$ ,1/√2]

k(x)= $\lim_{x\to\infty } \frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}$

k(x)= $\frac{7}{\infty}$

k(x)=0

5 0

3 years ago

Ok so the equation is 45+x=2x+15

sleet_krkn [62]

Answer:

y=45+x

y=2x+15

x=30

Step-by-step explanation:

3 0

3 years ago

Can anyone help me with this plz

inn [45]

Answer:

B.

Step-by-step explanation:

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Now we can look at the sides.

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They check out.

That means that the answer is B. SAS

5 0

3 years ago