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3 years ago

Jocelyn sells necklaces for $8 each. It costs her $20 for

Mathematics

1 answer:

Charra [1.4K]3 years ago

7 0

We see that the slope intercept is y = 8x - 20. So if we substitute x with 2, because x represents the amount of necklaces sold and we are analyzing her net profit after selling 2 necklaces, that gives us y = 8(2) - 20. Which simplifies to y = -4. So by the time Jocelyn sells 2 necklaces, her net profit will be at -4.

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Brut [27]

Answer:

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Step-by-step explanation:

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3 years ago

Mrs. Oliver drew a box plot to represent her students’ scores on a mid-term test.

Rzqust [24]

Answer:

About 1/4 scored higher and 3/4 scored lower

Step-by-step explanation:

84 is on the right side line

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2 years ago

Given the following inverse variation find the missing value: (5,-8) (20, y) find the missing value

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3 years ago

Which of the following equations represents a line that is perpendicular to y=3x+11 and intercepts the line at the point, (-2, 5

yaroslaw [1]

If the line is perpendicular the slope is the reciprocal so it would be
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3 years ago

A random sample of 150 men found that 88 of the men excercise regularly, while a random sample 200 women found that 130 of the w

melamori03 [73]

Answer:

The hypothesis is:

H₀: $p_{X}-p_{Y}=0$ .

Hₐ: $p_{X}-p_{Y}$ .

Step-by-step explanation:

Let X = number of men who exercise regularly and Y = number of women who exercise regularly.

The information provided is:

$n_{X}=150\\X=88\\n_{Y}=200\\Y=130$

Compute the sample proportion of men and women who exercise regularly as follows:

$\hat p_{X}=\frac{X}{n_{X}}=\frac{88}{150}=0.587$

$\hat p_{Y}=\frac{Y}{n_{Y}}=\frac{130}{200}=0.65$

The random variable X follows a Binomial distribution with parameters n = 150 and $\hat p_{X}=0.587$ .

The random variable Y also follows a Binomial distribution with parameters n = 200 and $\hat p_{Y}=0.65$ .

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

$\hat p=p$

The standard deviation of this sampling distribution of sample proportion is:

$\sigma_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}$

So, the sampling distribution of the proportion of men and women who exercise regularly follows a Normal distribution.

A two proportion z-test cab be performed to determine whether the proportion of women is more than men who exercise regularly.

The hypothesis for this test cab be defined as:

H₀: The proportion of women is same as men who exercise regularly, i.e. $p_{X}-p_{Y}=0$ .

Hₐ: The proportion of women is more than men who exercise regularly, i.e. $p_{X}-p_{Y}$ .

6 0

3 years ago

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