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stich3 [128]
3 years ago
7

Draw a flowchart that ask the user to enter number: if the number is less than then 10 number it is doubled if the number is mor

e than or equal to 10 one is added to it. the result is displayed the process is repeated until the number 0 is entered.
Computers and Technology
1 answer:
solong [7]3 years ago
8 0

Answer:

please find the attachment of the flowchart.

Explanation:

In this question, a start block is used to start the program, in the parallelogram box we input the value from the user end and in the diamond box, we check the input is not equal to 0. In the next diamond box, it checks the given input value and print value, and at the last, we stop the code.

Please find the program and its output in the attached file.

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Weak Induction
slega [8]

Answer:

Following are the answer to this question:

Explanation:

In option 1:

The value of n is= 7, which is (base case)

\to 3^7

when n=k for the true condition:

\to 3^k

when n=k+1 it tests the value:

\to 3^{(k+1)}= 3^k,3\\\to < (k!) 3 \ substituting \ equation \\\to

since k>6  hence the value is KH>3 hence proved.

In option 2:

when:

for n=1:(base case)

\log(1!)

0<=0 \\ condition is true

when the above statement holds value n=1

when n=k

\log(k!)

when n=k+1

\log(k+1)!=\log(k!)+\log(k+1)\\

             

\because k \log k      [\therefore KH>K \Rightarrow  \log(KH>\loK)]

In option 3:

when n=1:

A_1 \cup B=A_1 \cup B\\\\

when n=k

\to (A_1\cap A_2 \cap.....A_k) \cup B\\=(A_1\cup B) \cap(A_2\cup B_2)....(A_k \capB).....(a)\\\to n= k+1\\ \to (A_1\cap A_2 \cap.....A_{kH}) \cup B= (A_1\cup B)\\\\\to  [(A_1\cap A_2 \cap.....A_{k}) \cup B]\cap (A_{KH}\cup B)\\\\\to  [(A_1\cup B) \cap (A_2 \cup B) \cap (A_3\cup B).....(A_k\cup B)\cap (A_{k+1} \cup B)\\\\  \ \ \ \ \ \ substituting \ equation \ a \\\\

hence n=k+1 is true.

7 0
3 years ago
HELP ASAP!!!
stiks02 [169]
Comparison would be most suitable. I hope I could be a help


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<em></em>

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