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umka2103 [35]
3 years ago
15

3. The following is a dump of a UDP header in hexadecimal format. 0045DF000058FE20 a. What is the source port number? b. What is

the destination port number? c. What is the total length of the user datagram? d. What is the length of the data? e. Is the packet directed from a client to a server or vice versa? f. What is the client process?
Computers and Technology
1 answer:
balandron [24]3 years ago
6 0

Answer:

Explanation:

a) The source port number is the first four hexadecimal digits (0045), which

means that the source port number is 69.

b) The destination port number is the second four hexadecimal digits (DF00),

which means that the destination port number is 57088

c) The third four hexadecimal digits (0058) defines the length of the whole UDP packet as 88 bytes.

d) The length of the data is the length of the whole packet minus the length of the header, or 88 – 8 = 80 bytes.

e) Since the source port number is 69 (well-known port), the packet is from the client to the server.

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Given the function F (X, Y , Z)=Σm(0,1, 2 , 4 , 6)
Mnenie [13.5K]

Answer:

(1)Minterms complement = XYZ (2) Compliment of Minterms = Σm(0,1, 2 , 4 , 6) (3) (X+Y+Z) (4) Minimized SOP = Z + XY

Manterms = πM

Explanation:

Solution

Recall that:

Given the function F (X, Y , Z)=Σm(0,1, 2 , 4 , 6)

(1) Canonical Disjunctive Normal Form: In boolean algebra, the boolean function can be expressed as Canonical Disjunctive form known as minterms

In Minterm we assign 'I' to each uncomplimented variable and '0' to each complemented/complementary variable

For the given question stated we ave the following:

Minterms = XYZ, XYZ, XYZ, XYZ, XYZ.

(2) Canonical Conjunctive Normal Form: In boolean algebra, the boolean function can be expressed as Canonical Disjunctive form known as maxterms.

In Maxterms we assign '0' to each uncomplimented variable and '1' to each complemented/complementary variable

Compliment of Minterms = Σm(0,1, 2 , 4 , 6)

Maxterms = πM

Note: Kindly find an attached copy of the complete solution to this question below.

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