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Softa [21]
3 years ago
6

What is the answer to this? Please provide an explanation as well.

Mathematics
1 answer:
nikitadnepr [17]3 years ago
4 0

Answer:

z³ subtract z⁹ gives you z⁶ but it's a negative right now so you would flip it and get 1 over z6

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Which is the equation of the graphed line written in standard form? y = x x – 1/2y = 0 x – y = 0 y =1/2x
AysviL [449]

The standard for of this equation is x – y = 0

Firstly, options A and D are not in standard form, so they are not options.

To decided between B and C, we choose a point on the line and see if it works. For example, we'll use (2, 2).

x – y = 0

2 - 2 = 0

0 = 0

This is true for option C. Therefore, it is correct.

5 0
3 years ago
2<br> Solve for k.<br> -8k+ 6 = –10k + 10<br> k
Sever21 [200]

Answer:

k=2

Step-by-step explanation:

8 0
3 years ago
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What is mode and in 2hat ways can be find the mode of a given data!?​
avanturin [10]

Answer:

The mode of a data set is the number that occurs most frequently in the set. To easily find the mode, put the numbers in order from least to greatest and count how many times each number occurs. The number that occurs the most is the mode!

Step-by-step explanation:

internet.

6 0
3 years ago
A machine operation produces bearings whose diameters are normally distributed, with a mean of 0.497 inch and a standard deviati
eduard
Mean = 0.497 in, SD = 0.003 in
Required diameter ranges between 0.496 in and 0.504 in
Anything other diameter obtained is not acceptable.

That is;
P(x<0.496) and P(x>0.504) are not acceptable.

Now,
P(x<0.496) = P(Z< (0.496-0.497)/0.003)) = P(Z<-0.33)
From Z tables, P(Z<-0.33) = 0.3707

Similarly,
P(x>0.504) = P(Z> (0.504-0.497)/0.003)) = P(Z>2.33)
From Z tables, P(Z>2.33) = 1-0.9901 = 0.0099

Therefore, unacceptable proportion = P(x<0.496)+P(x>0.504) = 0.3707+0.0099 = 0.3806 or 38.06%
6 0
3 years ago
Let us consider a sequence <img src="https://tex.z-dn.net/?f=%5Crm%20a_%7Bn%7D" id="TexFormula1" title="\rm a_{n}" alt="\rm a_{n
kirill115 [55]

Hi there,

a_{5}=2850

Please check the attached image for answer.

<em>Hope </em><em>it </em><em>helps </em><em>.</em><em>.</em><em>.</em>

5 0
3 years ago
Read 2 more answers
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