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jolli1 [7]
3 years ago
11

An object is launched from the ground straight up with a initial velocity of 120 ft/s. how long will the rock be in the air?

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
7 0

Answer:

t = 7.5 seconds

Step-by-step explanation:

Givens

vi = 120 f/s

a = -32 f/s

d = 0               It goes up, stops and comes back down landing where it starts.

Formula

d = vi*t + 1/2 a t^2

Solution

0 = 120*t - 1/2*32*t^2     transfer 120t to the left

-120*t = - 1/2 32 t^2        Multiply 32 and 1/2 together  

- 120t = - 16 t^2                Divide both sides by t

-120 =    -16 t                    Divide by -16

-120/-16 = (-16/-16) * t      

t = 7.5 seconds

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Answer:

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Step-by-step explanation:

see the attached figure to better understand the problem

we know that

In the right triangle ABC of the figure, the tangent of angle C is equal to divide the opposite side to angle C (side AB) by the adjacent side to angle C (side BC)

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8 0
4 years ago
I Have No Idea How To Do This, Does Anyone Have An Idea To Calculate This?
Natasha2012 [34]

Answer:

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Step-by-step explanation:

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4 years ago
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Drupady [299]

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6 0
3 years ago
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Below

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4 years ago
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