Answer:
C. y₂ = (1 + (t/n))²
Step-by-step explanation:
yₙ₊₁ = yₙ + Δt F(tₙ, yₙ)
yₙ₊₁ = yₙ + Δt yₙ
yₙ₊₁ = yₙ + (t/n) yₙ
When n=0:
y₁ = y₀ + (t/n) y₀
y₁ = 1 + (t/n)
When n=1:
y₂ = y₁ + (t/n) y₁
y₂ = 1 + (t/n) + (t/n) (1 + (t/n))
y₂ = 1 + (t/n) + (t/n) + (t/n)²
y₂ = 1 + 2(t/n) + (t/n)²
y₂ = (1 + (t/n))²
Answer:
Diviértete tratando de conseguirlo porque no sé, así que sí, pero no
Step-by-step explanation:
Y= -10x + 190
In using a linear function, follow the pattern y=mx + b.
In this scenario, the m (which represents slope) is -10 since $10 is taken away every time. The b(which represents y-int) is 190 because you start with 190 (x=0)
(slope) The higher the gradient<span> of a graph at a point, the steeper the </span>line<span> is at that point.</span>
