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Elodia [21]
3 years ago
15

Question 4 (1 point) Do the ratios form a proportion? 8 32 4 , 12

Mathematics
1 answer:
PtichkaEL [24]3 years ago
8 0
Yes they do because you can simply them
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Single variable linear equation that has one solution
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Is the variable segment negative or positive determining for the answer
3 0
3 years ago
A computer randomly picks a number from the group 75, 76, 77, 78, 79.
Vanyuwa [196]
0.6 is the answer as its 3/5
7 0
3 years ago
"If a number divided by 4 leaves remainder 2 or 3", then which one is the correct statement 'n why?
Hoochie [10]

Answer:

As the number is a prime number. Therefore, option 'c' is true.

Step-by-step explanation:

Let us take the number 7 and divide it by 4

\frac{7}{4}

We know that

  • Quotient\frac{Remainder}{Divisor}

as

\frac{7}{4}=1\frac{3}{4}

so the remainder is 3.      ∵ Quotient\frac{Remainder}{Divisor}

As 7 is a prime number, and when we divide the prime number 7 by 4, we get the remainder 3.

Thus, the number is a prime number. Therefore, option 'c' is true.

5 0
3 years ago
GIVEN THAT TITAN HAS A RADIUS OF 2575 KM WHICH IS COVERED BY 600 KM ATMOSPHERE. WHAT
Ber [7]

Answer:

  87.4%

Step-by-step explanation:

The radius to the top of the atmosphere as a fraction of the moon's radius is ...

  (2575 +600)/2575 ≈ 1.23301

The ratio of the moon's volume with atmosphere to the moon's volume without is the cube of this, or 1.87456

Then the ratio of the atmosphere's volume to the moon's volume is ...

  (1.87456 -1)/1 = 0.87456

Atmospheric haze is about 87.4% of the moon's volume.

_____

We have assumed that the desired ratio is to the solid moon's volume, not the volume of moon and atmosphere together. The latter ratio would be 0.875 to 1.875 or about 46.7%.

3 0
3 years ago
The sequence$$1,2,1,2,2,1,2,2,2,1,2,2,2,2,1,2,2,2,2,2,1,2,\dots$$consists of $1$'s separated by blocks of $2$'s with $n$ $2$'s i
kicyunya [14]

Consider the lengths of consecutive 1-2 blocks.

block 1 - 1, 2 - length 2

block 2 - 1, 2, 2 - length 3

block 3 - 1, 2, 2, 2 - length 4

block 4 - 1, 2, 2, 2, 2 - length 5

and so on.


Recall the formula for the sum of consecutive positive integers,

\displaystyle \sum_{i=1}^j i = 1 + 2 + 3 + \cdots + j = \frac{j(j+1)}2 \implies \sum_{i=2}^j = \frac{j(j+1) - 2}2

Now,

1234 = \dfrac{j(j+1)-2}2 \implies 2470 = j(j+1) \implies j\approx49.2016

which means that the 1234th term in the sequence occurs somewhere about 1/5 of the way through the 49th 1-2 block.

In the first 48 blocks, the sequence contains 48 copies of 1 and 1 + 2 + 3 + ... + 47 copies of 2, hence they make up a total of

\displaystyle \sum_{i=1}^48 1 + \sum_{i=1}^{48} i = 48+\frac{48(48+1)}2 = 1224

numbers, and their sum is

\displaystyle \sum_{i=1}^{48} 1 + \sum_{i=1}^{48} 2i = 48 + 48(48+1) = 48\times50 = 2400

This leaves us with the contribution of the first 10 terms in the 49th block, which consist of one 1 and nine 2s with a sum of 1+9\times2=19.

So, the sum of the first 1234 terms in the sequence is 2419.

8 0
1 year ago
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