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3 years ago

Answer four please!! Thanks

Mathematics

1 answer:

Leya [2.2K]3 years ago

8 0

Answer:

I believe the second h=25+70t -16t

Step-by-step explanation:

because the initial height is 25 thats where you have to start and every second your adding 70 that way it's + 70t... but I don't get where the 16 comes in so I may be wrong

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Simply<br> (2k-9)^2+(k+2)^2=(2k+1)^2+(k-8)^2

vova2212 [387]

The square of a binomial expands as follows:

$(a+b)^2=a^2+2ab+b^2$

Expanding all the binomials, we have

$4k^2-36k+81+k^2+4k+4=4k^2+4k+1+k^2-16k+64$

Sum like terms:

$5k^2-32k+85=5k^2-12k+65$

Simplify terms appearing on both sides:

$-32k+85=-12k+65$

Move all terms involving k to the left and all numbers to the right:

$-20k=-20$

Divide both sides by -20:

$k=1$

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3 years ago

Identify one unique decimal that you encounter regularly during the week and how it affects you or not in your daily life. your

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A unique decimal that I encounter regularly is "0.05". I encounter this almost every day, when I go to the store to buy something, the saleslady gives me $0.05 as change. When I go home and put some of my extra money in my piggy bank, I hold a $0.05 in my hand.

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2 years ago

How many students were surveyed?<br>

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Answer:

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Can someone PLEASE help me with Trigonometry???

Svetach [21]

$\bf sin^2(2\theta)-7sin(2\theta)-1=0\\\\
-------------------------------\\\\
sin(2\theta)=\cfrac{7\pm\sqrt{49-4(1)(-1)}}{2(1)}\implies sin(2\theta)=\cfrac{7\pm\sqrt{49+4}}{2}
\\\\\\
sin(2\theta)=\cfrac{7\pm\sqrt{53}}{2}\implies 2\theta=sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)
\\\\\\
\theta=\cfrac{sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)}{2}$

but anyway, the numerator will give the angles, and θ is just half of each

$\bf \theta=\cfrac{sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)}{2}\\\\
-------------------------------\\\\
sin^{-1}\left( \frac{7+\sqrt{53}}{2} \right)\implies sin^{-1}(7.14)\impliedby \textit{greater than 1, no good}
\\\\\\
sin^{-1}\left( \frac{7-\sqrt{53}}{2} \right)\implies sin^{-1}(-0.14) \approx -8.05^o
\\\\\\
\theta=\cfrac{-8.05}{2}\implies \theta=-4.025$

ok... that's a negative tiny angle, is in the 4th quadrant, if we stick to the range given, from 0 to 360, so we have to use the positive version of it, 360-4.025

so the angle is 355.975°

now, the 3rd quadrant has another angle whose sine is negative, so... if we move from the 180° line down by 4.025, we end up at 184.025°

and those are the only two angles, because, on the 2nd and 1st quadrants, the sine is positive, so it wouldn't have an angle there

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3 years ago