The digit 5 in 4521 has a value that can be found by setting the other digits to zero. It is 500.
The digit 5 in 2615 has a value that can be found by setting the other digits to zero. It is 5.
500 is 100×5.
The digit 5 in 4521 has a value that is <em>100 times</em> the value of the digit 5 in 2615.
Answer: 3360
Step-by-step explanation: Reduce the expression, if possible, by cancelling the common factors.
The degree of this polynomial is 3, so it has to have 3 roots or 3 zeros.
If it has one non-repeated x-intercept, that means that this polynomial has ine real zero.
So, it needs 2 more, and this 2 are complex zero.
Correct answer is B. One real and 2 complex zeroes.
We calculate the cube root,
we know that
-0.000125-------------> is equal to -125/1000000-------->(-5³/10<span>^6)
</span>∛(-5³/10^6) = -5/10^2-------> -5/100--------> -0.05
The answer is -0.05
Answer:$99.36
Step-by-step explanation: When you’re doing these types of problems just use your calculator and do 108-8%
