Answer:
4
Step-by-step explanation:
Split 19 into two numbers, 9 and 10. If there are 10 nickels, there are 5 dimes. That means there rest are quarters and there are 4.
edit : im not american and have little knowledge of how much each are worth
Divide the long leg by the square root of 3 to find the short leg. Double that figure to find the hypotenuse.
Answer:
There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.
Step-by-step explanation:
Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.
The problem reduces to take 11 consecutive spots which we will use to localize the balls and the sticks and select 3 places to put the sticks. The amount of ways to do this is
As a result, we have 165 ways to distribute the blackboards.
If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is
. Thus, there are only 35 ways to distribute the blackboards in this case.
Step-by-step explanation:
Lets consider the unknown number as x
according to the question,
6-x= 5(x+2)
6-x= 5x+10
-x-5x=10-6
-6x=4
x=4/-6= 2/-3
x= -2/3
<em>hope this helps </em>
<em>please mark me as brainliest.</em>
Answer With Step-by-step explanation:
Part A:
.5[ (3x – 6) (2x + 4) ]
.5(6x^2 - 24)
3x^2 - 12
Part B:
Second Degree Binomial
Part C:
For Part A, a polynomial was multiplied by another polynomial. The resulting product was a polynomial. This is a demonstration of the closure property for multiplying polynomials.