All categories

2 years ago

What is the distance between the following 2 points on a coordinate

Mathematics

1 answer:

Tamiku [17]2 years ago

4 0

Answer:

C. 7.2

Step-by-step explanation:

D = $\sqrt{(-1-3)^2+(-2-4)^2}$

D = $\sqrt{16 + 36}$

D = $\sqrt{52}$

D = 7.2

You might be interested in

What is lim x→-3 sqrt x^2-8

vitfil [10]

If the -8 is under the square root, then...

$\displaystyle L = \lim_{x\to -3} \sqrt{x^2-8}\\\\L = \sqrt{(-3)^2-8}\\\\L = \sqrt{9-8}\\\\L = \sqrt{1}\\\\L = 1\\\\$

If the -8 is not under the square root, then...

$\displaystyle L = \lim_{x\to -3} \sqrt{x^2}-8\\\\L = \sqrt{(-3)^2}-8\\\\L = \sqrt{9}-8\\\\L = 3-8\\\\L = -5$

Either way, we replace x with -3 and simplify.

For more information, refer to the direct substitution rule for limits.

4 0

1 year ago

Here is a circle touching a square.

Alex Ar [27]

Answer: 9πcm²

Step-by-step explanation: area of the square= 36cm²

Therefore, the area of one side= √area = √36 = 6cms

Since the circle is touching the sides of the square, the side of the square = the diameter of the circle

Therefore the radius of the circle= side/2 = 3cm

The formula for the ares of the circle is πr²

π*3*3 = 9πcm²

8 0

2 years ago

jonah paid $25 for dues to a cub last year. This year he paid $35 for dues. By what percent did his dues increase

4vir4ik [10]

Answer:

40 % increase

Step-by-step explanation:

percent increase = (new - original)/ original

percent increase = (35-25)/25

= 10/25

=.4

multiply by 100

40 percent

4 0

3 years ago

Find the discriminant and determine the nature of the roots to the quadratic equation

Katen [24]

№17
$x^{2} +6x-7=0 \\ D=6 ^{2} -4*(-7)=36+28=64=8 ^{2} \\ \\ x_{1} = \frac{-6+8}{2} =1 \\ \\ x_{2} = \frac{-6-8}{2} =-7$
Answer: x₁ = 1
   x₂ = - 7

№18
$2 x^{2} -3x+4=3 \\ 2 x^{2} -3x+4-3=0 \\ 2 x^{2} -3x+1=0 \\ \\ D= -3 ^{2} -4*2=9-8=1 \\ \\ x_{1} = \frac{3+1}{2*2} = \frac{4}{4} =1 \\ \\ x_{2} = \frac{3-1}{2*2} = \frac{2}{4} =0.5$
Answer: x₁ = 1
     x₂ = 0,5.

№19
$2 x^{2} -4x-5=0 \\ D=-4 ^{2} -4*2*(-5)=16+40=56 \\ \\ x_{1}= \frac{4+ \sqrt{56} }{2*2} = \frac{4}{4} + \sqrt{ \frac{56}{16} } =1+ \sqrt{3.5} \\ \\ x_{2} = \frac{4- \sqrt{56} }{2*2} = \frac{4}{4} - \sqrt{ \frac{56}{16} } =1- \sqrt{3.5} 
$
Answer: x₁ = 1 + √3.5
     x₂ = 1 - √3.5

3 0

3 years ago

Plsss help i’ll give brainly...but pls give a correct answer

algol [13]

Answer:

Step-by-step explanation:

Terms are separated by symbols for operations (like plus, minus, multiply, divide.)

So your terms would be

-6

4 0

2 years ago

Read 2 more answers