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3 years ago

What is the distance between the following 2 points on a coordinate

Mathematics

1 answer:

Tamiku [17]3 years ago

4 0

Answer:

C. 7.2

Step-by-step explanation:

D = $\sqrt{(-1-3)^2+(-2-4)^2}$

D = $\sqrt{16 + 36}$

D = $\sqrt{52}$

D = 7.2

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Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

Lena will use 7 cups of apples to make 4 batches of applesauc. Which expression shows the number of cups of apples in each batch

astraxan [27]

Answer: 1 3/4 cups of apples in each batch

Step-by-step explanation:

STEP 1

Writing out the equation to represent if 7 cups of apples make 4 batches One batch is as a result of how many cups of apples

LET x be number of cups of apples to make each batch

7 cups of apples = 4 Batches

x cups of apples = 1 Batch

STEP 2 Solving by cross multiplication

1 batch x 7 cups of apples = 4 batches X x cups of apples

x cups of apples=1 batch x 7 cups of apples / 4batches

x = 7 / 4 = 1 3/4

number of cups of apples to make each batch= 1 3/4

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3 years ago

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3 years ago

Write an equation that has a graph with the shape of y = x^2, but shifted left 3 units.

svetoff [14.1K]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf % template detailing
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\$

$\bf \bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

now, with that template in mind, let's see

$\bf y=x^2\implies 
\begin{array}{llll}
y=(&1x&-0)^2\\
&B&C
\end{array}$

so, just change C to +3, thus C/B is 3/1

6 0

3 years ago