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3 years ago

Solve for x 2\3 = 18/x+5

Mathematics

1 answer:

Levart [38]3 years ago

7 0

If you could write out the whole problem exactly how it is, I can solve it for you.

You might be interested in

Which ordered pairs are solutions to the inequality 2x-y>1?

RideAnS [48]

Answer:

Any points in the shaded region including (2,-2) and (-3,-8)

Step-by-step explanation:

Convert the line into slope intercept form and graph it.

2x-y > 1 becomes -y>1-2x. Divide both sides by -1 and you get y<2x-1. Graph it with the shaded area on the right and a dashed line.

Any point which falls within the shaded red of the graph is a solution. No points on the line since it is not equal to (its dashed) are solutions. Check the location of your points to verify that they fall within this area.

(-3, -8) ---Yes

(-1, -3) ---No

(0, 5) --- No

(1, 6) --- No

(2, -2) ---Yes

8 0

3 years ago

4 • (6 – 4) 2 ÷ 2

Dmitry_Shevchenko [17]

Answer:

Cary is wrong

Step-by-step explanation:

4* (6-4)= 4* 2=8

I think it is saying (8*2) divided by to, which in that case is 8,

but if it is asking 8 (2/2) then that would also be 8 I believe. I really hope this is correct and you have a great day :)

5 0

3 years ago

Read 2 more answers

6.339m plus 0.170m plus 30.4m

77julia77 [94]

Answer:

36.909m

Step-by-step explanation:

6.339+0.170+30.4

=36.909m

7 0

2 years ago

1 year = how many seconds? Last question in my h.w and idk how to do it:/

Novay_Z [31]

This should help
60 sec = 1min
60min = 1 hour
24hour = 1day
7 days = 1 week
around 4.3 weeks = 1month
12 months = 1 year

or you could use 365 days and times that by 24 than times that by 60 to get mins and again by 60 to get seconds.

hope this helps

5 0

3 years ago

Sec squared 55 - tan squared 55

sergejj [24]

<u>Answer: </u>

sec squared 55 – tan squared 55 = 1

<u>Explanation:</u>

Given, sec square 55 – tan squared 55

We know that,

$\sec \Theta=\frac{\text {hypotenuse}}{\text {base}}$

And,

$\tan \theta=\frac{\text { perpendicular }}{\text { base }}$

where Ө is the angle

Substituting the values

$\left(\frac{\text {hypotenuse}}{\text {base}}\right)^{2}-\left(\frac{\text { perpendicular }}{\text {base}}\right)^{2}$

Solving,

$\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}$

According to Pythagoras theorem,

$\text { (hypotenuse) }^{2}-\text { (perpendicular) }^{2}=(\text { base })^{2}$

Putting this in the equation;

squared 55 - tan squared 55 =

$\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}=\frac{(\text {base})^{2}}{(\text {base}) *(\text {base})}=1$

Therefore, sec squared 55 – tan squared 55 = 1

6 0

3 years ago