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VMariaS [17]
3 years ago
5

Solve for x 2\3 = 18/x+5

Mathematics
1 answer:
Levart [38]3 years ago
7 0
If you could write out the whole problem exactly how it is, I can solve it for you.
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There are twice as many students on Mr. Sneed's team as on Mr. Johnson's team. Together, they want to raise 360$ to buy uniforms
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Answer:

720

Step-by-step explanation:

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What is 1 4/5 + 1 1/5??
Rudik [331]
1\dfrac{4}{5}+1\dfrac{1}{5}=(1+1)+\left(\dfrac{4}{5}+\dfrac{1}{5}\right)=2+\dfrac{1+4}{5}=2+\dfrac{5}{5}=2+1=3
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The volume (in cubic inches) of a shipping box is modeled by V =2x³ -19x² +39x, where x is the length (in inches). Determine the
yawa3891 [41]

Answer:

The values of x for which the model is 0 ≤ x ≤ 3

Step-by-step explanation:

The given function for the volume of the shipping box is given as follows;

V = 2·x³ - 19·x² + 39·x

The function will make sense when V ≥ 0, which is given as follows

When V = 0, x = 0

Which gives;

0 = 2·x³ - 19·x² + 39·x

0 = 2·x² - 19·x + 39

0 = x² - 9.5·x + 19.5

From an hint obtained by plotting the function, we have;

0 = (x - 3)·(x - 6.5)

We check for the local maximum as follows;

dV/dx = d(2·x³ - 19·x² + 39·x)/dx = 0

6·x² - 38·x + 39 = 0

x² - 19/3·x + 6.5 = 0

x = (19/3 ±√((19/3)² - 4 × 1 × 6.5))/2

∴ x = 1.288, or 5.045

At x = 1.288, we have;

V = 2·1.288³ - 19·1.288² + 39·1.288 ≈ 22.99

V ≈ 22.99 in.³

When x = 5.045, we have;

V = 2·5.045³ - 19·5.045² + 39·5.045≈ -30.023

Therefore;

V > 0 for 0 < x < 3 and V < 0 for 3 < x < 6.5

The values of x for which the model makes sense and V ≥ 0 is 0 ≤ x ≤ 3.

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3 years ago
Solve for x
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Mikel creates the table below to help her determine 40% of 70
DerKrebs [107]
40% percent times 70 is want I believe
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3 years ago
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