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3 years ago

Simplify the expression using properties of operations. (−r−5)−(−2r−4)

Mathematics

1 answer:

Pachacha [2.7K]3 years ago

8 0

Answer:r-1

Step-by-step explanation:

(-r-5)-(-2r-4) Or (-r-5)-(-2r-4)

-r+-5+2r+4. -r-5+2r+4

r-1 r-1

You bring down the first Parentheses Then have to multiply the (implied 1) -1•-2=2 and -1•-4=4 and do the math regularly

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zubka84 [21]

Answer:

$f(x) = \frac{108}{7} (\frac{7}{6})^x$ or $f(x) = 15.429(1.167)^x$

Step-by-step explanation:

No need for a calculator.

Assuming that the equation is in the form $y = ab^x$ , we can plug in points to get our equation. For ease, let's use (1,18) and (2,21). When plugging these points in, we get $18 = ab^1, 21 = ab^2$ . Now let's divide the equations to get rid of $a$ : $\frac{21 = ab^2}{18 = ab^1} = \frac{21}{18} = \frac{7}{6} = b$ . Now that we have $b$ , we can plug in the value we just calculated to solve for $a$ : $18 = a(\frac{7}{6} )^1$ , and solving for $a$ , we get $a = \frac{108}{7}$ .

So the $f(x) = (\frac{108}{7})(\frac{7}{6} )^x$

This equation in decimal form (rounded to the nearest thousandth) is $f(x) = 15.429(1.167)^x$ .

hope this helped! :)

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Step-by-step explanation:

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Step-by-step explanation:

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Read 2 more answers

The question is below:

Sonbull [250]

<h3>Hello There!!</h3><h2 /><h3><u>Given</u></h3>

$3(x - 2) + 7x = \frac{1}{2} (6x - 2)$

<h3><u>Solving </u><u>It</u></h3>

$3(x - 2) + 7x = \frac{1}{2} (6x - 2) \\ \\ \implies3x - 6 + 7x = ([\frac{1}{2} \times 6 \: x] - [\frac{1}{2} \times 2]) \\ \\ \implies10x - 6 = ([\frac{1}{ \cancel2} \times \cancel 6 \: x] - [\frac{1}{ \cancel2} \times \cancel2]) \\ \\ \implies 10x - 6 = 3x - 1 \\ \\ \fbox{Bringing (3x )to left side whereas( - 6 )in right side} \\ \\ \implies10x - 3x = - 1 + 6 \\ \\ \implies7x = 5 \\ \\ \therefore x = \frac{5}{7}$

The Solution is = $\frac{5}{7}$

$\text\red{One Solution set is possible.}$

<h3>Hope This Helps</h3>

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2 years ago