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erastova [34]
3 years ago
6

Find the perimeter??

Mathematics
2 answers:
DiKsa [7]3 years ago
7 0

Answer:

the perimeter of the triangle is 13in^{2}

Step-by-step explanation:

All you have to do is add up all the sides together, but first we need to find a common denominator, and it can be 12

3\frac{1}{3} = \frac{10}{3} = \frac{40}{12} ( i multiplied them by 4 (numerator and denominator))

4\frac{1}{6} = \frac{25}{6} = \frac{50}{12} ( i multiplied them by 2 (numerator and denominator))

5\frac{1}{2} = \frac{11}{2} = \frac{66}{12} ( i multiplied them by 6 (numerator and denominator))

Now that you have a common denominator for all 3 fractions, you can now add them all up

\frac{40}{12} + \frac{50}{12} + \frac{66}{12}

Now to add, the denominator has to stay the same (12), and add up all the numerators

\frac{40}{12} + \frac{50}{12} = \frac{90}{12} + \frac{66}{12} = \frac{156}{12} = 13 (simplified)

Hope this helped!

svp [43]3 years ago
3 0

Answer:

13 in

Step-by-step explanation:

just add all the numbers lol

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Area of a triangle with points at (-9,5), (6,10), and (2,-10)
Ann [662]
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Distance from point A to point B:
d_{AB}= \sqrt{[6-(-9)]^2+(10-5)^2}
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Distance from point A to point C:
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Distance from point B from point C
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d_{BC}= \sqrt{(-4)^2+(-20)^2}
d_{BC}= \sqrt{16+400}
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Now, we are going to find the semi-perimeter of our triangle using the semi-perimeter formula:
s= \frac{AB+AC+BC}{2}
s= \frac{15.81+18.60+20.40}{2}
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Finally, to find the area of our triangle, we are going to use Heron's formula:
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A=\sqrt{27.41(27.41-15.81)(27.41-18.60)(27.41-20.40)}
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We can conclude that the perimeter of our triangle is 140.13 square units.

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Step-by-step explanation:

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