All categories

3 years ago

Please help:D linear relationships/finding slope

Mathematics

2 answers:

Lady bird [3.3K]3 years ago

8 0

The slope is -4!!!!!!!!

yan [13]3 years ago

7 0

Answer:

give brainliest the slope is -4

Step-by-step explanation:

You might be interested in

Whats the difference between a sequence and a series?

snow_tiger [21]

Answer:

A sequence is defined as an arrangement of numbers in a particular order. On the other hand a series is defiend as the sum of the elements of a sequence!

3 0

3 years ago

Four equivalent expressions for 90+21

Kobotan [32]

All of the expressions must equal 111.

So it could be 91 + 20, 68 + 43, 45 + 66, 75 + 36, etc.

3 0

4 years ago

How much paint will you need to paint all sides of the box shown below? show work and use volume or surface area formula.

fiasKO [112]

Answer: 100

Explanation: triangle area is l x h ÷ 2 rectangle area is l x h. 4 x 3 =12÷2 +12÷2 =12 11x4x2= 88 88+ 12=100.

4 0

3 years ago

Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%. Find

Papessa [141]

Answer:

1) $\text{P(at least one boy and one girl)}=\frac{3}{4}$

2) $\text{P(at least one boy and one girl)}=\frac{3}{8}$

3) $\text{P(at least two girls)}=\frac{1}{2}$

Step-by-step explanation:

Given : Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%.

To Find : The probability of each event.

1) P(at least one boy and one girl)

2) P(two boys and one girl)

3) P(at least two girls)

Solution :

Let's represent a boy with B and a girl with G

Mr. and Mrs. Romero are expecting triplets.

The possibility of having triplet is

BBB, BBG, BGB, BGG, GBB, GBG, GGB, GGG

Total outcome = 8

$\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}$

1) P(at least one boy and one girl)

Favorable outcome = BBG, BGB, BGG, GBB, GBG, GGB=6

$\text{P(at least one boy and one girl)}=\frac{6}{8}$

$\text{P(at least one boy and one girl)}=\frac{3}{4}$

2) P(at least one boy and one girl)

Favorable outcome = BBG, BGB, GBB=3

$\text{P(at least one boy and one girl)}=\frac{3}{8}$

3) P(at least two girls)

Favorable outcome = BGG, GBG, GGB, GGG=4

$\text{P(at least two girls)}=\frac{4}{8}$

$\text{P(at least two girls)}=\frac{1}{2}$

4 0

4 years ago

Read 2 more answers

Find the quotient (X^2+x-20)(x-4)

lisabon 2012 [21]

Answer:

x + 5

Step-by-step explanation:

$\frac{x^{2} +x-20}{x-4}$

$\frac{(x-4)(x+5)}{x-4}$

x + 5

8 0

3 years ago