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3 years ago

Need answer ASAP

Mathematics

1 answer:

vova2212 [387]3 years ago

3 0

Answer:

Nicole is now 15 years old

Christine is now 5 years old

Step-by-step explanation:

x = age Nicole

y = age Christine

x = 3y

x+5 = 2×(y+5) = 2y + 10

3y + 5 = 2y + 10

y + 5 = 10

y = 5

x = 3y = 3×5 = 15

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Can someone help me pls

Whitepunk [10]

Answer:

AB = 18

Step-by-step explanation:

tan 45° = 18/AB

1 = 18/AB

AB = 18

5 0

3 years ago

Evaluate the expression for k = -11. -k − 11 =

valkas [14]

k = -11

-k - 11 = ?

-11 - 11 = ?

The answer is -22.

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8 0

4 years ago

Ht) = -16t+32t+ 10.

KonstantinChe [14]

Answer:
16t + 10

Explanation:
Step 1 - Add like terms

-16t + 32t + 10
16t + 10

5 0

4 years ago

What is the unit rate of 180 miles in 3 hours

Tems11 [23]

The unit rate would be:

180 mi/3h

=60 mi/h

Therefore the unit rate would be 60 miles per hour

4 0

3 years ago

Read 2 more answers

A closed box with a square base is to have a volume of 171 comma 500 cm cubed. The material for the top and bottom of the box co

Zepler [3.9K]

Answer:

$C(x)=\dfrac{20x^3+1715000}{x}\\$Minimum cost, C(35)=\$29,400$

The dimensions that will lead to minimum cost of the box are a base length of 35 cm and a height of 140 cm.

Step-by-step explanation:

Volume of the Square-Based box=171,500 cubic cm

Let the length of a side of the base=x cm

Volume $=x^2h$

$x^2h=171,500\\h=\dfrac{171500}{x^2}$

The material for the top and bottom of the box costs $10.00 per square centimeter.

Surface Area of the Top and Bottom $=2x^2$

Therefore, Cost of the Top and Bottom $=\$10X2x^2=20x^2$

The material for the sides costs $2.50 per square centimeter.

Surface Area of the Sides=4xh

Cost of the sides=$2.50 X 4xh =10xh

$\text{Substitute h}$=\dfrac{171500}{x^2} $into 10xh\\Cost of the sides=10x(\dfrac{171500}{x^2})=\dfrac{1715000}{x}$

Therefore, total Cost of the box

$= 20x^2+\dfrac{1715000}{x}\\C(x)=\dfrac{20x^3+1715000}{x}$

To find the minimum total cost, we solve for the critical points of C(x). This is obtained by equating its derivative to zero and solving for x.

$C'(x)=\dfrac{40x^3-1715000}{x^2}\\\dfrac{40x^3-1715000}{x^2}=0\\40x^3-1715000=0\\40x^3=1715000\\x^3=1715000\div 40\\x^3=42875\\x=\sqrt[3]{42875}=35$

Recall that:

$h=\dfrac{171500}{x^2}\\Therefore:\\h=\dfrac{171500}{35^2}=140cm$

The dimensions that will lead to minimum costs are base length of 35cm and height of 140cm.

Therefore, the minimum total cost, at x=35cm

$C(35)=\dfrac{20(35)^3+1715000}{35}=\$29,400$

8 0

3 years ago