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vivado [14]
3 years ago
15

Astronauts on the International Space Station commonly face a health issue that some people on Earth experience as well. Researc

h conducted on this health issue has helped solve problems on Earth.
What is this health issue?
(1 point)
a weightlessness

b hearing and sight loss

c loss of bone and muscle density

d obesity
Mathematics
2 answers:
elena-14-01-66 [18.8K]3 years ago
8 0
C is the correct answer
Ludmilka [50]3 years ago
4 0

Answer:

C

Step-by-step explanation:

In space you have to exercise 24/7, because if you don't your bones will decay little by little, the same goes for earth, it is a condition that happens if you don't move or exercise.

If possible; can I get brainliest, I mean if it's correct

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A=4-b<br>2a+b=1<br><br>SIMULTANEOUS EQUATIONS<br>help pls​
nasty-shy [4]

Plug in for a

2(4-b)+b=1

8-2b+b=1

8-b=1

b=7

Step-by-step explanation:

8 0
3 years ago
What is the solution to the system graphed below?
Feliz [49]

Answer:

Option D.

Step-by-step explanation:

We need to find the solution to the system graphed below.

If a system of equation have 2 linear equation then the intersection point of both lines lines is the solution of the system of equations.

In the given graph two straight lines intersect each other at (-1,-1).

Point of intersection = (-1,-1)

So, by using the given graph we can conclude that the solution of given system of equations is (-1,-1).

Therefore, the correct option is D.

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3 years ago
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X &lt; -5. solve plssss no links​
kondor19780726 [428]

Answer: I don't know how to type the infinity symbol on my phone but..

(-infinity, -5)

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4 0
3 years ago
Differentiate x^2 e^x logx
zimovet [89]

Product rule:

\dfrac{\mathrm d}{\mathrm dx}(x^2e^x\log x)

=\dfrac{\mathrm d(x^2)}{\mathrm dx}e^x\log x+x^2\dfrac{\mathrm d(e^x)}{\mathrm dx}\log x+x^2e^x\dfrac{\mathrm d(\log x)}{\mathrm dx}

Power rule:

\dfrac{\mathrm d(x^2)}{\mathrm dx}=2x

The exponential function is its own derivative:

\dfrac{\mathrm d(e^x)}{\mathrm dx}=e^x

Assuming the base of \log x is e, its derivative is

\dfrac{\mathrm d(\log x)}{\mathrm dx}=\dfrac1x

But if you mean a logarithm of arbitrary base b, we have

y=\log_bx\implies x=b^y=e^{y\ln b}\implies1=e^{y\ln b}\ln b\dfrac{\mathrm dy}{\mathrm dx}

\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{e^{-y\ln b}}{\ln b}=\dfrac1{b^y\ln b}

\implies\dfrac{\mathrm d(\log_bx)}{\mathrm dx}=\dfrac1{x\ln b}

So we end up with

2xe^x\log x+x^2e^x\log x+\dfrac{x^2e^x}x

=xe^x(2\log x+x\log x+1)

8 0
3 years ago
What number is greater?
lesantik [10]
10 is greater because it equals 3.162...
3 0
4 years ago
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