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vesna_86 [32]
3 years ago
7

Identify the following function What kind of function do it shows ?

Mathematics
1 answer:
ahrayia [7]3 years ago
5 0
The vertical line test can be used to determine whether a graph represents a function. A vertical line includes all points with a particular x value. The y value of a point where a vertical line intersects a graph represents an output for that input x value
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Angeline would like to make 8 identical bowls for a gift to her family. Each bowl required 34 lbs. of clay. The clay is sold in
Makovka662 [10]

Answer:

it would take 7 packs for one so  she will need 56 bags

Step-by-step explanation:

8x34=272

7x8 =56

4 0
3 years ago
PLEASE HELP ME WITH THESE<br> ALL WORK IS APPRECIATED!!<br> THANK YOU:)❤️
Vsevolod [243]

3) In Δ BDC

|DC|/|BC| = cos C

cos C= 16/17.89

C= cos⁻¹( 16/17.89)=26.57⁰

In triangle ABC:

x=180-(90+26.57)=63.43

x=63.43

2)

AB/BD= tan(70⁰), AB=BD*tan(70⁰)

AB/BC=tan(40⁰), AB=BC*tan(40⁰)

BD*tan(70⁰)=BC*tan(40⁰)

BD=BC-CD=BC - 15

(BC -15)*tan(70⁰)=BC*tan(40⁰)

BC*tan(70⁰) -15*tan(70⁰)= BC*tan(40⁰)

BC*tan(70⁰) - BC*tan(40⁰) = 15*tan(70⁰)

BC(tan(70⁰)-tan(40⁰))= 15*tan(70⁰)

BC = 15*tan(70⁰)/(tan(70⁰)-tan(40⁰)) = 21.60

BC=21.60

1) In a quadrilateral sum of angles =360⁰.

PQS=SQR=50⁰, because SQ bisects PQR.

Using Law of sine in ΔSRQ

SR/sin ∠SQR = SQ/sinR, SQ = SR * sinR/sin SQR = 3*sin30/sin50 =3.26

SQ=3.26 cm

ΔPQS:

cos PQS= PQ/SQ

PQ=SQ*cosPQS =3.26*cos 50⁰=2.09=2.1

PQ=2.1 cm


3 0
3 years ago
Х<br> – 5<br> 1<br> 4<br> 6<br> 1<br> у<br> 9<br> 0<br> -7<br> —1<br> Range
Wittaler [7]

Answer: 16

Step-by-step explanation:

Range is the largest number in the set minus the smalllest number in the set pf numbers or data.

9-(-7)

9+7

16

4 0
3 years ago
Read 2 more answers
4x+2y=5 , 2x-3y=13 pair of equations to two decimal places of accuracy. ​
slavikrds [6]

Answer:

x = 2.56, y = -2.63

Step-by-step explanation:

I first multiplied the second equation by two, getting

4x-6y = 26

I then subtracted the equations

 4x+2y = 5

- 4x-6y = 26

--------------------

      8y = -21

y = -2.63

with y solved, I plugged it into the second equation to get x:

2x-3(-2.63) = 13

2x+ 7.89 = 13

2x = 5.11

x = 2.56

I hope this helped! ;D

6 0
3 years ago
Please help me lol a lil confused
alex41 [277]

\leadsto f( \rm x) =  - (x - 3)(x - 5)

\\  \\

\leadsto f( \rm x) =   - ( {x}^{2}  - 5x - 3x + 15) \\

\\  \\

\leadsto f( \rm x) =   - ( {x}^{2}   - 8x + 15) \\

\\  \\

\leadsto f( \rm x) =   - {x}^{2}  + 8x  -  15 \\

3 0
3 years ago
Read 2 more answers
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