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Mice21 [21]
3 years ago
15

How can i put the number 103,727,495 in expanded form

Mathematics
1 answer:
tia_tia [17]3 years ago
7 0
How can i put the number 103,727,495 in expanded form
You can put the number 103, 727,495 in expanded form by:
<span><span>1.       </span>100, 000, 000 + 3,000, 000 + 700,000 + 20, 000 + 7, 000 + 400 + 90 + 5</span>

Which in words is.

<span><span>1.       </span>One hundred three million seven hundred twenty seven thousand four hundred ninety-five </span>



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Answer:37

Step-by-step explanation:

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Mr. Lee bought rock to landscape around his house. He bought seven ton of rock for $151.13. How much did the rock cost per ton?
Mazyrski [523]

Answer:

A. $21.59

Step-by-step explanation:

$151.13 ÷ 7 tons= $21.59 each per ton

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Read 2 more answers
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Answer:
9.1

Explanation:
Use the distance formula
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Answer 11-12 it’s ok if your don’t no one of them. Please do at least one. Thanks.
Naddika [18.5K]

[11]

Equation: 180° - 75°

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3 0
3 years ago
Cholesterol levels for a group of women aged 30-39 follow an approximately normal distribution with mean 190.14 milligrams per d
Anettt [7]

Answer:

Step-by-step explanation:

Hello!

X: Cholesterol level of a woman aged 30-39. (mg/dl)

This variable has an approximately normal distribution with mean μ= 190.14 mg/dl

1. You need to find the corresponding Z-value that corresponds to the top 9.3% of the distribution, i.e. is the value of the standard normal distribution that has above it 0.093 of the distribution and below it is 0.907, symbolically:

P(Z≥z₀)= 0.093

-*or*-

P(Z≤z₀)= 0.907

Since the Z-table shows accumulative probabilities P(Z<Z₁₋α) I'll work with the second expression:

P(Z≤z₀)= 0.907

Now all you have to do is look for the given probability in the body of the table and reach the margins to obtain the corresponding Z value. The first column gives you the integer and first decimal value and the first row gives you the second decimal value:

z₀= 1.323

2.

Using the Z value from 1., the mean Cholesterol level (μ= 190.14 mg/dl) and the Medical guideline that indicates that 9.3% of the women have levels above 240 mg/dl you can clear the standard deviation of the distribution from the Z-formula:

Z= (X- μ)/δ ~N(0;1)

Z= (X- μ)/δ

Z*δ= X- μ

δ=(X- μ)/Z

δ=(240-190.14)/1.323

δ= 37.687 ≅ 37.7 mg/dl

I hope it helps!

8 0
3 years ago
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