Answer:
Step-by-step explanation:
Given that a flyer begins from earth and thrown up with a velocity of 30 ft/sec vertically.
u = initial velocity = 30 : a = -g = 32 ft/sec^2
s(0) =initial height =4 ft.
We have the equation
where u = initial velocity : v= final velocity : s = distance travelled and a = acceleration. Here final velocity is found out as follows
Substitute to get
Since v cannot be negative, the flyer’s center of gravity cannot ever reach 20 feet.
----------------------------------
To reach 25 ft, put s = 25
and v must be atleast 0
Then we have
Hence if thrown with initial velocity of 40 ft /sec, it will reach a height of 25 ft.
Answer: (B) min = -14, max = -3
<u>Step-by-step explanation:</u>
The minimum is the y-value of the vertex of a positive (U-shaped) parabola. In the graph, the vertex is located at (4.5, -14). The y-value of the vertex is -14.
The maximum is the y-value of the vertex of a negative (∩-shaped) parabola. In the graph, the vertex is located at (1.5, -3). The y-value of the vertex is -3.
It would be D because you add the the 3 and the 5 and you get 8
73.94 X .33 = 24.40 thats how much the markup (or profit is)
73.94 + 24.40 = 98.34 thats how much they sold it for.
