Ask question

Ask question

All categories

4 years ago

15

Which Relationships have the same constant of proportionality between Y and X the following table?

1 answer:

Lorico [155]4 years ago

5 0

Do you have a picture?

You might be interested in

There are 12 red checkers and 3 black checkers in a bag. Checkers are selected one at a time, with replacement. Each time, the c

Firdavs [7]

I will use the binomial distrubion to find the probability.

$\displaystyle
P(A)=\binom{n}{k}p^k(1-p)^{n-k}$

------------------------------------------------------

A - selecting a red checker exactly 7 times in 10 selections

$n=7\\
k=10$

$\displaystyle
P(A)=\binom{10}{7}\cdot\left(\dfrac{12}{15}\right)^7\cdot\left(1-\dfrac{12}{15}\right)^{10-7}\\\\
P(A)=\dfrac{10!}{7!3!}\cdot\left(\dfrac{4}{5}\right)^7\cdot\left(1-\dfrac{4}{5}\right)^3\\\\
P(A)=\dfrac{8\cdot9\cdot10}{2\cdot3}\cdot\dfrac{16384}{78125}\cdot\left(\dfrac{1}{5}\right)^3\\\\
P(A)=120\cdot\dfrac{16384}{78125}\cdot\dfrac{1}{125}\\\\
P(A)=\dfrac{393216}{1953125}\approx0.2=20\%$

5 0

3 years ago

Type the missing number that makes these fractions equal:?/84=18/28

Rzqust [24]

Answer:

la respuesta es 54/84

Step-by-step explanation:

54/84=0,642857

18/28=0.642857

8 0

3 years ago

Circles that share a common center but no other common points are called:

aleksklad [387]

I guess concentric circles

3 0

3 years ago

i serve mom 1/12 and my brother 1/6 of the pot how much of the pot is left what operation should I use

Mumz [18]

The operation would be: 1-1/12-1/6=1-3/12=9/12=3/4
Good luck!

4 0

3 years ago

Read 2 more answers

Complete the statements.

spayn [35]

Answer:

1. 30

2. 150

Step-by-step explanation:

$3tan^2(x)-1 =0$

Lets assume tan(x) = u

$3u^2(x)-1 =0$

Now we solve for 'u'

add 1 on both sides

$3u^2(x) =1$ , divide both sides by 3

$u^2 = \frac{1}{3}$

Take square root on both sides

$u = +-\frac{1}{\sqrt{3} }$

We replace tan(x) for 'u'

$tan(x) = +-\frac{1}{\sqrt{3} }$

x = 30 because $tan(30) =+\frac{1}{\sqrt{3} }$ in first quadrant

x = 30 (tan is positive in first quadrant)

$tan(x) =-\frac{1}{\sqrt{3} }$

x = 150 because $tan(150) =-\frac{1}{\sqrt{3} }$ in second quadrant

tan is negative in second quadrant

4 0

4 years ago