Answer:
zero
Step-by-step explanation:
Answer:
اhello : tan θ = - 12/5
Step-by-step explanation:
tan θ = sin θ / cos θ .... (*)
(cosθ)² + (sinθ)² = 1 ... (**)
theta is in quadrant 2 : cosθ ≤ 0
Substitute sinθ = 12/13 into (**) and solve for cosθ :
(cosθ)² + (12/13)² = 1
(cosθ)² = 1 - 144/169
(cosθ)² = 25/169
cosθ = - 5 /13 because cosθ ≤ 0
by (*) : tan θ = (12/13)/ (-5/13) = (12/13) ×(-13/5)
tan θ = - 12/5
Answer:
-1 
, -1.75, 3/11, 0.3
Step-by-step explanation:
Negatives are always less then positive, so they would go first since its least to greatest.
7/9 = 0.77 which means -1 7/9 = -1.77, therefore it is less then -1.75
-1.75 would be next
3/11 = 0.2 which is less then 0.3 so it would go next.
and at last, goes 0.3 as the greatest number.
Answer:
The rate at which the radius is decreasing when the radius is 6 cm is approximately 3.316 × 10⁻³ cm/s
Step-by-step explanation:
The rate at which air is being lost from the balloon = 3/2 cm³/s
The rate at which the radius is decreasing when the radius is 6 cm long is given as follows;
The rate at which air is being lost from the balloon = dV/dt = 3/2 cm³/s
dV/dt = dV/dr × dr/dt
Where;
dr/dt = The rate at which the radius is decreasing
dV/dr = d(4/3×π×r³)/dr = 4·π·r²
Therefore, we have;
dr/dt = (dV//dt)/(dV/dr) = (3/2 cm³/s)/(4·π·r²)
dr/dt = (3/2 cm³/s)/(4·π·r²)
When r = 6 cm, we have;
dr/dt = (3/2 cm³/s)/(4 × π × (6 cm)²) ≈ 3.316 × 10⁻³ cm/s
Therefore, the rate at which the radius is decreasing, dr/dt, when the radius is 6 cm long ≈ 3.316 × 10⁻³ cm/s.
