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aliya0001 [1]
3 years ago
12

Cgggggggggggggggggggg image ggggggggggggggggggggggggggggg

Mathematics
1 answer:
Lilit [14]3 years ago
5 0

9514 1404 393

Answer:

  • x = 30
  • y = 105
  • z = 75

Step-by-step explanation:

You know the linear pair z° and 105° are supplementary angles, so ...

  z = 180 -105 = 75

The other base angle of the isosceles triangle has the same measure, 75°. __

Then x can be found either from the sum of interior angles of the triangle, or from the relation of 105° to the "remote interior angles". The first relation gives ...

75° +75° +x° = 180°   ⇒   x = 180 -150 = 30

The second relation gives ...

  75° +x° = 105°   ⇒   x = 105 -75 = 30

__

y° is supplementary to the left-side base angle, so is ...

  y = 180 -75 = 105

Of course, you could also figure y from the symmetry of the figure.

The values of x, y, z are 30, 105, 75, respectively.

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You are graphing Rectangle ABCDABCDA, B, C, D in the coordinate plane. The following are three of the vertices of the rectangle:
emmainna [20.7K]

Answer:

Rectangle ABCDABCDA, B, C, D is graphed in the coordinate plane. vertices of the rectangle: A(-1, -6),A(−1,−6),A, left parenthesis, minus, 1, comma, minus, 24+2 ps y+4 sr y+5 qR 2x + 3 pq 2y+2.

Step-by-step explanation:

8 0
3 years ago
What is the equation of a vertical line passing through the point (−4, 7)? y = 7 y = −4 x = 7 x = −4
Katen [24]
The equation of the vertical line passing through point -4,7 would be X = -4.
8 0
3 years ago
Read 2 more answers
together,sarah's two cats have the same mass as her dog,11 kg.the mass of one cat is 1500 g greater than the mass of the other.
Alika [10]
Let (a) be the first cat
let (b) be the second cat
a +b=11kg-----(1)
a=b+1500g⇒(1.5 kg)-------(2)
so now u have a system of two unknowns
a=11-b
substitute a in (2)
11-b=b+1.5
11-1.5=2b
2b=9.5
b=9.5/2=4.75
subs. b in (1)
a+b=11
a+4.75=11
a=11-4.75=6.25
so cat (a) is 6.25 kg
and (b) is 4.75 kg
hope I helped



6 0
2 years ago
Twelve cans of peaches are placed into each box. Write a function rule for the number of boxes needed for c cans. How many boxes
Mars2501 [29]

C = # of cans

b = # of boxes                          

C  |  B    

12 |  1

24 | 2

36 | 3


12b = C

12b/12 = 1440/12

b = 120 boxes

for 1440 cans.

6 0
2 years ago
A manager records the repair cost for 14 randomly selected dryers. A sample mean of $88.34 and standard deviation of $19.22 are
s2008m [1.1K]

Answer:

Hence the 90% confidence interval estimate of the population mean is (79.24 , 97.44)

Step-by-step explanation:

Given that,  

Point estimate = sample mean = \bar x = 88.34  

sample standard deviation = s = 19.22  

sample size = n = 14  

Degrees of freedom = df = n - 1 = 13  

Critical value =t\alpha /2, df = 1.771

 

Margin of error

E = t\alpha/2,df \times (\frac{s}{\sqrt{n} } )\\= 1.771 \times (19.22 / \sqrt 14)  

Margin of error = E = 9.10  

The 90% confidence interval estimate of the population mean is,  

\bar x - E < \mu < \bar x + E\\\\88.34 - 9.10 < \mu < 88.34 + 9.10\\\\79.24 < \mu < 97.44\\(79.24 , 97.44)

8 0
2 years ago
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