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pantera1 [17]
2 years ago
7

At George Washington High School, the ratio of graduating seniors that go on to college compared to those who do not is 7 : 4. L

ast year, 28 students did not go on to college. How many students did?
Mathematics
1 answer:
wolverine [178]2 years ago
8 0
Hi, thank you for posting your question here at Brainly.

This problem can be solved easily by applying ratio and proportion. In this case, the ratio between those who go to college and those who do not is 7/4. Then, when there are 28 students, you can determine the number of which who don't go to college by using the 7/4 ratio value

7/4 = 28/x
x = 16

Thus, 16 students did not go on to college. 
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let's firstly convert the mixed fractions to improper fractions and then to do away with the denominators, let's multiply both sides by the LCD of all denominators.

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Line segment AB has endpoints A(-1.5, 0) and B(4.5 8). Point C is on line segment AB located at (0, 2)
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Answer:

The ratio of AC/CB=1/3

Step-by-step explanation:

We use the section formula:

(\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n})

We substitute the point A(-1.5,0) and B(4.5,8).

We plug in the points to get:

(\frac{4.5m - 1.5n}{m+n},\frac{8m+n \times 0}{m+n})

This is supposed to be equal to: (0,2).

(\frac{4.5m - 1.5n}{m+n},\frac{8m+n \times 0}{m+n}) = (0,2)

We can equate, corresponding coordinates to find m and n.

\frac{4.5m - 1.5n}{m + n}  = 0

This implies that:

4.5m - 1.5n = 0

4.5m  = 1.5n

\frac{m}{n}  =  \frac{1.5}{4.5}

\frac{m}{n}  =  \frac{1}{3}

Therefore the ratio is m:n=1:3

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3 years ago
in circle F, points A,B,C,D, and E are located on the circle such that measure of C=119°, and BE is perpendicular AD. determine
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Answer:

Measure of arc AE = 58°

Step-by-step explanation:

As shown: ABCD is a quadrilateral, ∠C = 119°

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Arc AE opposite to the angle ∠ABG

So, measure of arc AE = 2∠ABG = 2 * 29° = 58°

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