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eimsori [14]
3 years ago
9

On a coordinate plane, rhombus W X Y Z is shown. Point W is at (7, 2), point X is at (5, negative 1), point Y is at (3, 2), and

point Z is at (5, 5).
What is the perimeter of rhombus WXYZ?

StartRoot 13 EndRoot units
12 units
StartRoot 13 EndRoot units
20 units
Mathematics
2 answers:
EleoNora [17]3 years ago
6 0

Answer:

C on edge 2021

Step-by-step explanation:

I took the cumulative exam

Otrada [13]3 years ago
5 0

Answer:

P = 4\sqrt{13}

Step-by-step explanation:

Given

W = (7, 2)

X = (5, -1)

Y = (3, 2)

Z =(5, 5)

Required

The perimeter

To do this, we first calculate the side lengths using distance formula

d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2

So, we have:

WX = \sqrt{(5- 7)^2 + (-1 - 2)^2

WX = \sqrt{13}

XY = \sqrt{(3-5)^2 + (2--1)^2}

XY = \sqrt{13}

YZ = \sqrt{(5-3)^2 + (5-2)^2}

YZ = \sqrt{13}

ZW = \sqrt{(7 - 5)^2 + (2 - 5)^2}

ZW = \sqrt{13}

The perimeter is:

P = WX + XY + YZ + ZW

P = \sqrt{13}+\sqrt{13}+\sqrt{13}+\sqrt{13}

P = 4\sqrt{13}

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