3. Use compass and straightedge to bisect T. Describe your process carefully and clearly.
1 answer:
Check the picture attached
let the rays forming angle T be ray 1 and ray 2
Draw a circle with center point T. Let the intersection of the circle with rays 1 and 2 be at points A and B respectively.
Draw 2 circles with centers A and <span>B so that:
The radii (radius'es) are equal, and they are large enough to intersect.
Denote the intersection of these 2 circles with C.
Join T to C. The line through T and C is the bisector.</span>
let the rays forming angle T be ray 1 and ray 2
Draw a circle with center point T. Let the intersection of the circle with rays 1 and 2 be at points A and B respectively.
Draw 2 circles with centers A and <span>B so that:
The radii (radius'es) are equal, and they are large enough to intersect.
Denote the intersection of these 2 circles with C.
Join T to C. The line through T and C is the bisector.</span>
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Consider the expression 
To factorize the expression in the denominator we use difference of squares:
To factorize
we use the following method:
where a, b are 2 numbers such that a+b= -1, the coefficient of x,
and a*b= -6, the constant.
such 2 numbers can be easily checked to be -3 and 2
(-3*2=6, -3+2=-1)
So
for x>2
thus
for x>2,
Answer:
for x>2
, (but the expression is never 0)
To factorize the expression in the denominator we use difference of squares:
To factorize
where a, b are 2 numbers such that a+b= -1, the coefficient of x,
and a*b= -6, the constant.
such 2 numbers can be easily checked to be -3 and 2
(-3*2=6, -3+2=-1)
So
for x>2
thus
for x>2,
Answer:
for x>2