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nalin [4]
3 years ago
9

Find the unit rate. $11.40 for 6 gallons

Mathematics
1 answer:
OverLord2011 [107]3 years ago
3 0

Answer:

$ 1.90 for 1 Gallon

Step-by-step explanation:

11.40/6 = 1.90

another way you can show the answer is: $1.90/1 Gal.

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Sam is earning money by mowing lawns, while his friend Will is getting paid to tutor. Sam's money can be represented by the func
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Answer:

6363536

Step-by-step explanation:

becayse

7 0
2 years ago
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A jar contains 100 marbles. There are 10 blue marbles, 79 green marbles, 6 red marbles, and 5 yellow marbles. What is the probab
ad-work [718]

To find the probability of pulling something first take note of the total number and the amount of which you want to select.

100 and 10

Now set them up as a fraction

10/100 and simplify

1/10 or 10%

6 0
3 years ago
What type of association does the graph show between x and y
Arturiano [62]

Answer:

As X gets bigger, Y gets smaller.

Step-by-step explanation:

Every time X gets larger, the Y coordinates go down.

6 0
3 years ago
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Fifteen bicyclists entered a race. In how many different orders can the top five finish so that awards can be given?
postnew [5]

Answer:

They can finish the race in 15 x 14 x 13 x 12 x 11 = 360360 order.

Step-by-step explanation:

There are 15 bicyclists in the race. The first position would come from the first bicyclist to the 15th. Meaning the first position can be occupied by 15 individuals. The second position can only be occupied by 14 individuals since one person is already first. Same way the third, fourth and fifth positions can be occupied by 13, 12 and 11 individuals respectively.

Therefore, they can finish the race in

15 x 14 x 13 x 12 x 11 = 360360 order.

5 0
3 years ago
Can anyone do 4,5 and 6 for me plz
cricket20 [7]

For  question 4, sinA =\frac{a}{c}, cosA= \frac{b}{c}, tan B = \frac{b}{a}, sin J = \frac{j}{l}, cosK = \frac{j}{l}, tanK = \frac{k}{j}.

Question 5. Option a and question 6. Option j

Step-by-step explanation:

Step 1:

The three basic formula needed to solve these questions are:

sin\theta = \frac{oppositeside}{hypotenuse} , cos\theta = \frac{adjacentside}{hypotenuse}, tan\theta= \frac{opposite side}{adjacent side}.

Step 2:

Using the above formula, we solve the following values

sinA = \frac{oppositeside}{hypotenuse}  =\frac{a}{c}.

cosA = \frac{adjacentside}{hypotenuse} = \frac{b}{c}.

tanB= \frac{opposite side}{adjacent side}= \frac{b}{a}.

sinJ = \frac{oppositeside}{hypotenuse} = \frac{j}{l}.

cosK = \frac{adjacentside}{hypotenuse}= \frac{j}{l}.

tanK= \frac{opposite side}{adjacent side}= \frac{k}{j}.

Step 3:

For question 5, The triangle's angle = 23°, opposite side = BC inches and hypotenuse = 4 inches.

sin\theta= \frac{opposite side}{hypotenuse}. sin 23^{\circ}= \frac{BC}{4}, sin23^{\circ} = 0.3907,BC = (0.3907)(4) = 1.5628.

SO BC is 1.5628 inches, rounding this off to the nearest tenth, we get BC = 1.6 inches which is option a.

Step 4:

For question 6, The triangle's angle = 50°, opposite side = QR m the adjacent side = 8.1 m.

tan\theta= \frac{opposite side}{adjacentside}. tan 50^{\circ}=\frac{QR}{8.1}, tan50^{\circ} = 1.1917,QR = (1.1917)(8.1) = 9.65277

SO QR is 9.65277 meters, rounding this off to the nearest tenth, we get QR = 9.7 inches which is option j.

7 0
3 years ago
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