Answer:
<h2>
$26.25</h2>
<em><u>Solving steps:</u></em>
<em>Question:</em> <u>Sam had some money in his pocket, and he found another $6. 50 in his dresser drawer. He then had a total of $19. 75. Let p represent the amount of money Sam had in his pocket. Which equation can you use to find the amount of money Sam had in his pocket? How much money did Sam have in his pocket?.</u>
<em>Find: </em><em> </em><u>How much money did Sam have in his pocket?.</u>
<em>Solution:</em><em> </em>Let the equation be
<h3><em>=> P = T </em><em>+</em><em>F</em></h3>
<u>p represent amount of money</u>
<u>p represent amount of moneyt represent total</u>
<u>p represent amount of moneyt represent totalf represent money found</u>
<h3>
<em>=> P = T </em><em>+</em><em> </em><em>F</em></h3>
<u>insert the values</u>
<h3><em>=> P = $19.75 </em><em>+</em><em> </em><em>$6.50</em></h3>
add<u> 19.75 from 6.50 </u>
<h3><em>=> P = </em><em> </em><em>26.25</em></h3>
<em><u>THEREFORE THE AMOUNT OF MONEY </u></em><em><u>SAM</u></em><em><u> HAVE IN HIS POCKET</u></em><em><u> IS ABOUT</u></em><em><u> </u></em><em><u> </u></em><em><u>$</u></em><em><u>26.25</u></em>
Answer:
y=45x+25
Step-by-step explanation:
y=45x+25
25 is a one-time fee so it is at the end. 45 is the monthly fee so it goes in front of x.
Answer:
a1 = 2
d = 3
an = 2 + (n - 1) * 3
a7 = 20
a59 = 176
Steps:
a1 is the initial value (when n equals 1), and since there are 2 crosses, it is 2.
d is the added value to each amount of crosses. And since the second amount is 5 and the third amount is 8, we can determine that each n is adding 3 crosses, therefore making d = 3.
The equation is simply plugging in the values for a1 and d.
A7 is simply plugging in 7 for n in the equation and solving for it. So;
a7 = 2 + (7 - 1) * 3
a7 = 2 + 6 * 3
a7 = 2 + 18
a7 = 20
And same thing as the last for 59 except substitute 59 in for where you put 7;
a59 = 2 + (59 - 1) * 3
a59 = 2 + 58 * 3
a59 = 2 + 174
a59 = 176
We're looking for the two values being subtracted here. One of these values is easy to find:
<span>g(1) = ∫f(t)dt = 0</span><span>
since taking the integral over an interval of length 0 is 0.
The other value we find by taking a Left Riemann Sum, which means that we divide the interval [1,15] into the intervals listed above and find the area of rectangles over those regions:
</span><span>Each integral breaks down like so:
(3-1)*f(1)=4
(6-3)*f(3)=9
(10-6)*f(6)=16
(15-10)*f(10)=10.
So, the sum of all these integrals is 39, which means g(15)=39.
Then, g(15)-g(1)=39-0=39.
</span>
I hope my answer has come to your help. God bless and have a nice day ahead!
