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lbvjy [14]
3 years ago
12

suppose six of these people are men, and the other six are women. in how many ways can they join hands for a circle dance, assum

ing they alternate in gender around the circle
Mathematics
1 answer:
Drupady [299]3 years ago
8 0

Twelve people join hands for a circle dance.In how many ways can they do this? Suppose six of these people are men, and the other six are women. In how many ways can they join hands for a circle dance, assuming they alternate in gender around the circle

Answer:

86400 ways

Step-by-step explanation:

Since the circle can be rotated, the number of ways to arrange a distinct number of n objects in a circle will be (n−1)!.

Now, if we rotate the circle with the six women, we will see that there are 5! ways with which they can be placed in the circle.

After picking the places for the women, we will now fill each gap between two women with a man.

We have 6 men. Thus, number of ways to arrange the men is 6!

Thus,number of ways they can join hands for a circle dance, assuming they alternate in gender around the circle = 5! × 6! = 86400 ways

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Assuming that you multiply 5600 by 8% which would end up being 448.

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What is the answer to this equation <br><br> h(x)= -9 - x; h(2k-5
dezoksy [38]

The answer is h(2k - 5) = -4 - 2k

Step-by-step explanation:

In a function f(x) = y, we can find the value of y for any given value of x

Examples:

  • If f(x) = 2x - 3, and we need to find f(3), that means substitute x by 3 in f(x), so f(3) = 2(3) - 3 = 6 - 3 = 3, that means f(x) = 3 at x = 3
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∵ h(x) = -9 - x

- We need to find h(2k - 5), that means substitute x by 2k - 5

∵ x = 2k - 5

∴ h(2k - 5) = -9 - (2k - 5)

- Simplify the right hand side

∴ h(2k - 5) = -9 - 2k - (-5)

- Remember (-)(-) = (+)

∴ h(2k - 5) = -9 - 2k + 5

- Add the like terms in the right hand side

∴ h(2k - 5) = (-9 + 5) - 2k

∴ h(2k - 5) = -4 - 2k

The answer is h(2k - 5) = -4 - 2k

Learn more:

You can learn ore about the functions in brainly.com/question/5337932

#LearnwithBrainly

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