Answer:
Final temperature is 29,8°C
Explanation:
For the reaction:
HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l)
You have 0,05000L*1,00M = 0,0500 moles of HCl ≡ moles of NaOH
The heat realeased by this reaction with these amounts is:
q = 57,3kJ/mol*0,0500mol = 2,865 kJ ≡ 2865J
The formula of heat capacity is:
q=C×ΔT×m
Where q is the heat released (2865 J)
C is specific heat capacity (4,184J/g°C)
m is mass (50 mL of NaOH+50 mL of HCl = 100 mL ≡ 100g -by density of solution=1,00g/mL-
ΔT is final T- initial T (X-23)
Replacing:
2865 J = 4,184J/g°C×100g×(X-23°C)
6,8 = X-23
X = 29,8°C
<em>Final temperature is 29,8°C</em>
I hope it helps!