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3 years ago

PLEASE HELP ME !?!?!?!?

Mathematics

1 answer:

Lina20 [59]3 years ago

3 0

I’m sorry but it’s shows a black screen

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A salesperson works 40 hours per week at a job where she has two options for being paid. Option A is an hourly wage of $28. Opt

seropon [69]

I hope this helps . Good luck

4 0

3 years ago

Determine whether argument is valid 12. P-> p q ܆܇

Alik [6]

Answer:

I think you meant $P\geq p*q$

It would false

Step-by-step explanation:

4 0

3 years ago

12.5-0.009= 1.25-0.009= 0.75-0.009= 1.20-0.009=

tia_tia [17]

Hello! Here are your Answers:

12.5 - 0.009 = 12.491

1.25 - 0.009 = 1.241

0.75 - 0.009 = 0.741

1.20 - 0.009 = 1.191

I hope This Helps!

6 0

3 years ago

34 = 10 + 4q Solve Need help

LiRa [457]

Simplifying

34 = 10 + 4q

Solving

34 = 10 + 4q

Solving for variable 'q'.

Move all terms containing q to the left, all other terms to the right.

Add '-4q' to each side of the equation.

34 + -4q = 10 + 4q + -4q

Combine like terms: 4q + -4q = 0

34 + -4q = 10 + 0

34 + -4q = 10

Add '-34' to each side of the equation.

34 + -34 + -4q = 10 + -34

Combine like terms: 34 + -34 = 0

0 + -4q = 10 + -34

-4q = 10 + -34

Combine like terms: 10 + -34 = -24

-4q = -24

Divide each side by '-4'.

q = 6

Simplifying

q = 6

hope this helps please mark brainliest

6 0

4 years ago

Data consistent with summary quantities in the article "Effects of Fast-Food Consumption on Energy Intake and Diet Quality Among

Olegator [25]

Answer:

a) X[bar]₁= 1839.20 cal

b) X[bar]₂= 1779.07 cal

c) S₁= 386.35 cal

Step-by-step explanation:

Hello!

You have two independent samples,

Sample 1: n₁= 15 children that did not eat fast food.

Sample 2: n₂= 15 children that ate fast food.

The study variables are:

X₁: Calorie consumption of a kid that does not eat fast food in one day.

X₂: Calorie consumprion of a kid that eats fast food in one day.

The point estimate of the population mean is the sample mean

X[bar]₁= (∑X₁/n₁) = (27588/15)= 1839.20 cal

X[bar]₂= (∑X₂/n₂)= (26686/15)= 1779.07 cal

To calculate the sample standard deiation, you have to calculate the sample variance first:

S₁²= $\frac{1}{n_1-1}$ [∑X₁² - (( ∑X₁)²/n₁)]= $\frac{1}{14} + [52829538 - (\frac{27588^{2} }{15})$ = 149263.4571 cal²

S₁= 386.35 cal

I hope it helps!

7 0

3 years ago