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Alexxandr [17]
3 years ago
12

F Which conditions are sufficient to prove a quadrilateral is a square?

Mathematics
1 answer:
Tresset [83]3 years ago
7 0

Answer:

I think the answer is a .

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In 2012, entering freshmen at the UA have an average ACT score of 25.4 with a standard deviation of 2.1. 1. What is the probabil
astra-53 [7]

Answer:

 P [ Z >  24,1 ] =  72,24 %

Step-by-step explanation:

P [ Z > 24,1 ]  =  1  - P [ Z < 24,1 ]

P [ Z < 24,1 ] = ( Z - μ₀ ) / σ

P [ Z < 24,1 ] = ( 24,1 - 25,4) / 2,1

P [ Z < 24,1 ] = - 1,3/ 2,1

P [ Z <  24,1 ] = - 0,6190  ≈ - 0,62

We look in z-table and find for  z(score) -0,6190

P [ Z <  24,1 ] = 0,27763

Then

P [ Z >  24,1 ] = 1 - 0,27763

P [ Z >  24,1 ] = 0,72237    ⇒    or       P [ Z >  24,1 ] =  72,24 %

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3 years ago
What percent of 33 is 34
Viktor [21]
11.22 is 33% of 34 if that is what youre asking
3 0
3 years ago
Read 2 more answers
Which is the graph of the system of equations?
Wewaii [24]
The graph of the equation is the first one; the y-intercept of the first equation is -4 and the y-intercept of the second equation is -8
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3 years ago
If the volume of a pyramid is 100 cubic inches, and the area of the base is 25 square inches, what is the height of the
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Answer:

12 inches

Step-by-step explanation:

It will be the right answer

6 0
3 years ago
A fair die is rolled fourfour times. A 2 is considered​ "success," while all other outcomes are​ "failures." Find the probabilit
Alja [10]
<h2>Answer:</h2>

Hence, the probability is:

            \dfrac{1}{6^4}\ or\ 0.000772

<h2>Step-by-step explanation:</h2>

It is given that:

A fair die is rolled four times. A 2 is considered​ "success," while all other outcomes are​ "failures."

This means that the probability of 4 successes is the outcome such that each of the four die will result in the outcome 2.

Also, the probability of 2 in each of the die is: 1/6

( since, there are total 6 outcomes in a die {1,2,3,4,5,6} and out of which there is only one '2' )

Also, we know that the outcome on one die is independent on the other this means that  the probability of 4 successes is:

=\dfrac{1}{6}\times \dfrac{1}{6}\times \dfrac{1}{6}\times \dfrac{1}{6}\\\\\\\\=\dfrac{1}{6^4}\\\\\\=0.000772

3 0
3 years ago
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