Brandon is thinking of two numbers. Their sum is - 10 and their difference is -2.

Mathematics

1 answer:

GrogVix [38]3 years ago

5 0

Answer:

x+y=-10

x-y=-2

Step-by-step explanation:

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60 + 7.20 + 7.80 please math is so dumb

Alja [10]

75
60+7.20= 67.20
67.20+7.80= 75

6 0

3 years ago

2 2/7× 5 1/6<br><br>what is the answer to this question pls tell me

hodyreva [135]

Answer:

7 19/42

Step 1:

Convert the mixed fractions into improper fraction (Denominator will be same)

2x7+2= 16/7

5x6+1=31/6

Step 2:

LCM of 6 and 7 are 42

Step 3:

217+96/42= 313/42

Step 4:

Covert to mixed fraction so the answer is 7 19/42

7 0

3 years ago

Read 2 more answers

Consider a game in which a participant pays $2 to roll a die. The participant receives $3 if they roll a 1 (i.E. They go up by a

Sauron [17]

Answer:

The expected monetary value of a single roll is $1.17.

Step-by-step explanation:

The sample space of rolling a die is:

S = {1, 2, 3, 4, 5 and 6}

The probability of rolling any of the six numbers is same, i.e.

P (1) = P (2) = P (3) = P (4) = P (5) = P (6) = $\frac{1}{6}$

The expected pay for rolling the numbers are as follows:

E (X = 1) = $3

E (X = 2) = $0

E (X = 3) = $0

E (X = 4) = $0

E (X = 5) = $0

E (X = 6) = $4

The expected value of an experiment is:

$E(X)=\sum x\cdot P(X=x)$

Compute the expected monetary value of a single roll as follows:

$E(X)=\sum x\cdot P(X=x)\\=[E(X=1)\times \frac{1}{6}]+[E(X=2)\times \frac{1}{6}]+[E(X=3)\times \frac{1}{6}]\\+[E(X=4)\times \frac{1}{6}]+[E(X=5)\times \frac{1}{6}]+[E(X=6)\times \frac{1}{6}]\\=[3\times \frac{1}{6}]+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]\\+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]+[4\times \frac{1}{6}]\\=1.17$