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vichka [17]
3 years ago
8

Find the quotient of 6a3 ÷ 3a.

Mathematics
2 answers:
Volgvan3 years ago
8 0
6a^3 : 3a = 2a^3-1 = 2a^2

The quotient is 2a^2

Hope it helped
Nat2105 [25]3 years ago
7 0
Assuming that the "3" behind the a is the exponent

So, \frac{6a^3}{3a} Replace the 3 with a 2

 Now, \frac{6a^2}{3}

\frac{6a}{3a}  = 2a

Answer: 2a^2

good \\ luck \\ on \\ your \\ assignment \\ \\ \\ enjoy \\ your \\  day! \\ \\ \\ MeIsKaitlyn :)
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for 6

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3 years ago
Someone help me!!! Please, i only have a few minutes :(
GuDViN [60]

Answer:

true, false

Step-by-step explanation:

4 0
3 years ago
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PLEASEEEEEEEEEEEEEEEEEE URGENT
jeyben [28]

Option C:

f(x) = 5x + 7 is the function of the input-output table.

Solution:

Option A: f(x) = 6x + 9

Input x = 1 in the above equation.

f(1) = 6(1) + 9

    = 6 + 9

f(1) = 15

But the output is 12 in the table.

So, it is not the function of the table.

Option B: f(x) = 7x + 5

Input x = 1 in the above equation.

f(1) = 7(1) + 5

f(1) = 12

Input x = 5 in the above equation.

f(5) = 7(5) + 5

f(5) = 40

But the output is 32 in the table.

So, it is not the function of the table.

Option C: f(x) = 5x + 7

Input x = 1 in the above equation.

f(1) = 5(1) + 7

f(1) = 12

Input x = 5 in the above equation.

f(5) = 5(5) + 7

f(5) = 32

Input x = 10 in the above equation.

f(10) = 5(10) + 7

f(10) = 57

Input x = 5 in the above equation.

f(15) = 5(15) + 7

f(15) = 82

All outputs are correct for the given input.

Hence it is the function of the table.

Option D: f(x) = 12x + 1

Input x = 1 in the above equation.

f(1) = 12(1) + 1

f(1) = 12

Input x = 5 in the above equation.

f(5) = 12(5) + 1

f(5) = 61

But the output is 32 in the table.

So, it is not the function of the table.

Hence Option C is the correct answer.

f(x) = 5x + 7 is the function of the input-output table.

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