Answer:
<u>Congruent pairs of triangles:</u>
ΔABD ≅ ΔDCB
- AB≅CD - given
- ∠ABD ≅ ∠CDB - given
- BD≅DB - common side
- SAS - two sides and the included angle
ΔABD ≅ ΔEFD - SAS
- AB≅EF - given
- ∠ABD ≅ ∠EFD - given
- ∠ADB ≅ ∠EDF - vertical angles
- AAS - two angles and non-included side
<u>By using the above two we can state that:</u>
ΔBDC ≅ ΔDFE - by ASA or SSS
because
- BD ≅ DF (corresponding parts)
- AD ≅ BC (corresponding parts)
- AD ≅ ED (corresponding parts)
- and therefore BC ≅ ED
<u>We can't prove that:</u>
- ΔAGD is congruent with any of the others as not enough information
There is one side and one angle and we can' t get two angles or two sides with included angle. Maximum we can get is SSA which doesn't guarantee the congruence.
Answer:
power of a power
Step-by-step explanation:
the power of a power law says that, "if a base raised to a power is being raised to another power, the exponents are multiplied and the base remains the same."
for example, for this problem, you would do:
![(x^4)^9\\= x^4^*^9\\= x^3^6](https://tex.z-dn.net/?f=%28x%5E4%29%5E9%5C%5C%3D%20x%5E4%5E%2A%5E9%5C%5C%3D%20x%5E3%5E6)
I think it is $10 for 20%
The value of the function h(x + 1) is -x^2 - x + 1
<h3>How to evaluate the function?</h3>
The equation of the function is given as:
h(t) =-t^2 + t + 1
The function is given as:
h(x + 1)
This means that t = x + 1
So, we substitute t = x + 1 in the equation h(t) =-t^2 + t + 1
h(x + 1) =-(x + 1)^2 + (x + 1) + 1
Evaluate the exponent
h(x + 1) =-(x^2 + 2x + 1) + x + 1 + 1
Expand the brackets
h(x + 1) = -x^2 - 2x - 1 + x + 1 + 1
Evaluate the like terms
h(x + 1) = -x^2 - x + 1
Hence, the value of the function h(x + 1) is -x^2 - x + 1
Read more about functions at:
brainly.com/question/1415456
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<u>Complete question</u>
Consider the following function definition, and calculate the value of the function
h(t) = −t2 + t + 1 h(x + 1)