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Artemon [7]
3 years ago
5

Use implicit differentiation to solve that the derivative

Mathematics
1 answer:
Len [333]3 years ago
7 0

Given

<em>e</em> ˣʸ = sec(<em>x</em> ²)

take the derivative of both sides:

d/d<em>x</em> [<em>e</em> ˣʸ] = d/d<em>x</em> [sec(<em>x</em> ²)]

Use the chain rule:

<em>e</em> ˣʸ d/d<em>x</em> [<em>xy</em>] = sec(<em>x</em> ²) tan(<em>x</em> ²) d/d<em>x</em> [<em>x</em> ²]

Use the product rule on the left, and the power rule on the right:

<em>e</em> ˣʸ (<em>x</em> d<em>y</em>/d<em>x</em> + <em>y</em>) = sec(<em>x</em> ²) tan(<em>x</em> ²) (2<em>x</em>)

Solve for d<em>y</em>/d<em>x</em> :

<em>e</em> ˣʸ (<em>x</em> d<em>y</em>/d<em>x</em> + <em>y</em>) = 2<em>x</em> sec(<em>x</em> ²) tan(<em>x</em> ²)

<em>x</em> d<em>y</em>/d<em>x</em> + <em>y</em> = 2<em>x</em> <em>e</em> ⁻ˣʸ sec(<em>x</em> ²) tan(<em>x</em> ²)

<em>x</em> d<em>y</em>/d<em>x</em> = 2<em>x</em> <em>e</em> ⁻ˣʸ sec(<em>x</em> ²) tan(<em>x</em> ²) - <em>y</em>

d<em>y</em>/d<em>x</em> = 2<em>e</em> ⁻ˣʸ sec(<em>x</em> ²) tan(<em>x</em> ²) - <em>y</em>/<em>x</em>

Since <em>e</em> ˣʸ = sec(<em>x</em> ²), we simplify further to get

d<em>y</em>/d<em>x</em> = 2 tan(<em>x</em> ²) - <em>y</em>/<em>x</em>

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