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3 years ago

Use point-slope form to find the equation of the line passing through (0,5) with a slope of 2/3

1 answer:

7 0

Answer: y - 5 = 2/3(x - 0)

Explanation:

Point slope form:

y - y1 = m(x - x1)
Given information:
y1 = 5
x1 = 0
m = 2/3

We can write the equation using the form:

y - 5 = 2/3(x - 0)

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Name the property shown in the equation: 4 x (5 + 6) = (4 x 5) + (4 x 6)

Novosadov [1.4K]

The property used in the equation is called Distributive property.

<h3>What is Distributive property?</h3>

The distributive Property States that when a factor is multiplied by the sum/addition of two terms, it is essential to multiply each of the two numbers by the factor, and finally perform the addition operation.

Given an equation, 4 x (5 + 6) = (4 x 5) + (4 x 6)

The property used in this equation is distributive property.

a(b+c) = (a*b)+(a*c)

Hence, The property used in the equation is called Distributive property.

For more references on Distributive property, click;

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8 0

11 months ago

Solve this please math problem asap please

Gennadij [26K]

Answer:

Step-by-step explanation:

Hope this helps

4 0

2 years ago

Read 2 more answers

Find the LCM of n^3 t^2 and nt^4.<br><br> A) n 4t^6<br> B) n 3t^6<br> C) n 3t^4<br> D) nt^2

patriot [66]

Answer:

The correct option is C.

Step-by-step explanation:

The least common multiple (LCM) of any two numbers is the smallest number that they both divide evenly into.

The given terms are $n^3t^2$ and $nt^4$ .

The factored form of each term is

$n^3t^2=n\times n\times n\times t\times t$

$nt^4=n\times t\times t\times t\times t$

To find the LCM of given numbers, multiply all factors of both terms and common factors of both terms are multiplied once.

$LCM(n^3t^2,nt^4)=n\times n\times n\times t\times t\times t\times t$

$LCM(n^3t^2,nt^4)=n^3t^4$

The LCM of given terms is $n^3t^4$ . Therefore the correct option is C.

8 0

2 years ago

Read 2 more answers

Find an equation of the circle and sketch it if it has: Center on y=4, tangent x-axis at (–2, 0)

Digiron [165]

Answer:

$(x+2)^2+(y-4)^2=16$

OK, lets start by drawing a basic graph (the first one) so we can visualize.

We already know that the y coordinate of the circle's center is $4$ .

We know that the circle is tangent to the $X$ axis at $(-2,0)$

That means the x coordinate of the center has to be $-2$ , as the tangent is a point on the edge of the circle that touches a line at exactly one point.

The radius is the distance from the center of the circle to its edge. We know the center's location now, it is $(-2, 4)$ and a point on the edge of the circle (the tangent point) which is $(-2,0)$ . so the distance between the points is 4 which is the radius (you can use the distance formula, but it's quite oblivious.)

We can imagine the circle should look like this (the second one):

Now we can piece together an equation

The equation of a circle is $(x-h)^2+(y-k)^2=r^2$ where $(h,k)$ is the center and $r$ is the radius. When we put the numbers in: we get $(x-(-2))^2+(y-(4))^2=4^2$ which can be simplified into $(x+2)^2+(y-4)^2=16$ which is the answer.