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3 years ago

Given: LINE AB≅ LINE CB, LINE AD≅ LINE CD, ANGLE BAD≅ ANGLE BCD, LINE BD bisects ANGLE ABC

Mathematics

1 answer:

sveta [45]3 years ago

4 0

Answer:

Step-by-step explanation:

Statements Reasons

1). AB ≅ CB, AD ≅ CD 1). Given

2). BD ≅ BD 2). Reflexive Property of congruence

3). ∠BAD ≅ ∠BCD 3). Given

4). ∠ABD ≅ ∠CBD 4). Given

5). ∠BDA ≅ ∠BDC 5). Third angles theorem

6). ΔABD ≅ ΔCBD 6). SAS property of congruence of two

triangles

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Each students in class 38 students was asked to report how many siblings he has. Data a 0/38 Data b 1/38 Data c 13/38 Data 8/38

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Answer:

8/38

Step-by-step explanation:

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3 years ago

Please help I dont understand

Katena32 [7]

The slope is 3, count from one point to o other. If you go from -2,0 up to -1,3 you go up 3 and over one so the slope is 3

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3 years ago

Read 2 more answers

A teacher places n seats to form the back row of a classroom layout. Each successive row contains two fewer seats than the prece

Alex_Xolod [135]

Answer:

The number of seat when n is odd $S_n=\frac{n^2+2n+1}{4}$

The number of seat when n is even $S_n=\frac{n^2+2n}{4}$

Step-by-step explanation:

Given that, each successive row contains two fewer seats than the preceding row.

Formula:

The sum n terms of an A.P series is

$S_n=\frac{n}{2}[2a+(n-1)d]$

$=\frac{n}{2}[a+l]$

a = first term of the series.

d= common difference.

n= number of term

l= last term

$n^{th}$ term of a A.P series is

$T_n=a+(n-1)d$

n is odd:

n,n-2,n-4,........,5,3,1

Or we can write 1,3,5,.....,n-4,n-2,n

Here a= 1 and d = second term- first term = 3-1=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=1 and d=2

$n=1+(t-1)2$

⇒(t-1)2=n-1

$\Rightarrow t-1=\frac{n-1}{2}$

$\Rightarrow t = \frac{n-1}{2}+1$

$\Rightarrow t = \frac{n-1+2}{2}$

$\Rightarrow t = \frac{n+1}{2}$

Last term l= n,, the number of term $=\frac{ n+1}2$ , First term = 1

Total number of seat

$S_n=\frac{\frac{n+1}{2}}{2}[1+n}]$

$=\frac{{n+1}}{4}[1+n}]$

$=\frac{(1+n)^2}{4}$

$=\frac{n^2+2n+1}{4}$

n is even:

n,n-2,n-4,.......,4,2

Or we can write

2,4,.......,n-4,n-2,n

Here a= 2 and d = second term- first term = 4-2=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=2 and d=2

$n=2+(t-1)2$

⇒(t-1)2=n-2

$\Rightarrow t-1=\frac{n-2}{2}$

$\Rightarrow t = \frac{n-2}{2}+1$

$\Rightarrow t = \frac{n-2+2}{2}$

$\Rightarrow t = \frac{n}{2}$

Last term l= n, the number of term $=\frac n2$ , First term = 2

Total number of seat

$S_n=\frac{\frac{n}{2}}{2}[2+n}]$

$=\frac{{n}}{4}[2+n}]$

$=\frac{n(2+n)}{4}$

$=\frac{n^2+2n}{4}$

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3 years ago

A professor has recorded exam grades for 20 students in his class, but one of the grades is no longer readable. If the mean sco

Ivenika [448]

Answer:

Step-by-step explanation:

To obtain the total score for all the 20 students, we multiply the average score by the number hence

Total score for all 20 is 81*20=1620

Similarly, for the 19 students, the sum of their total score equals the product of the average and number of students hence

Total score for 19 readable is 19*85=1615

The difference between these two total scores ie for 20 and 19 students equals to the value of unreadable score. Therefore,

Difference=1620-1615=5

Therefore, the value of unreadable score is 5

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3 years ago

This how dog looks like<br> She looking like a rat

Sati [7]

Answer:

Awe she is so cute!!!!!!! She looks like a Brown lab and a poodle mix. I WISH I COULD HAVE HER!

Step-by-step explanation:

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3 years ago