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Roman55 [17]
3 years ago
13

Angle sec0= -13/12 and cot<0. what are the exact values of tan0 and sin0.

Mathematics
2 answers:
Arturiano [62]3 years ago
4 0

Answer:

tan 0= -2.4

sin 0 = 0.42

Step-by-step explanation:

sec 0 = -13/12 => cos 0 = -12/13

cot 0 < 0 => tan 0 < 0

so, the angle is on second quadrant

=> tan 0 = -12/5 = -2.4

=> sin 0 = 5/12 = 0.42

bija089 [108]3 years ago
3 0

Answer:

Solution given;

Sec θ=-\frac{13}{12}

cotθ< 0,

It lies in second quadrant.

where sin and cosec is positive.

Now

\frac{1}{cosθ}=-\frac{13}{12}

cosθ=\frac{12}{13}

\frac{b}{h}=\frac{12}{13}

b=12

h=13

By using Pythagoras law

p=\sqrt{13²-12²}=5

Now

exact values of tan θ=\frac{p}{b}=\frac{5}{12}

since it lies in II quadrant

tan θ=-\frac{5}{12}

and

sinθ=\frac{p}{h}=\frac{5}{13}

since it lies in II quadrant

sin θ=\frac{5}{13}

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