Answer: 6
Explanation: first you have to get rid of the 2 power of 3, 2 x 2 x 2 is 8. Then 15-8=7. Then 42➗7 is 6
This is how you write 5.24 in expanded form 5+0.2+0.04
Answer:
<h3><u>Required Answer</u><u>:</u><u>-</u></h3>







The first pipe pumps out

while the second pipe pumps out

So together, both pipes pump out

That is, with both pipes filling the tank, it should take 32 minutes total.
Answer:
0.7823 = 78.23% probability that the response time is between 3 and 9 minutes.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 7.2 minutes and a standard deviation of 2.1 minutes.
This means that 
For a randomly received emergency call, find the probability that the response time is between 3 and 9 minutes.
This is the pvalue of Z when X = 9 subtracted by the pvalue of Z when X = 3.
X = 9



has a pvalue of 0.8051
X = 3



has a pvalue of 0.0228
0.8051 - 0.0228 = 0.7823
0.7823 = 78.23% probability that the response time is between 3 and 9 minutes.