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2 years ago

Find the value of x. 120

Mathematics

1 answer:

shutvik [7]2 years ago

6 0

Answer:

46 degrees

Step-by-step explanation:

if you look at it closely u can see that the 120 degrees is reflected to the opposite side so if the 120 degrees is reflected then the 46 degrees would be reflected too

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A machinist uses a special tool to measure the diameter of a small pipe. The measurement tool reads 0.276 inch. What is this mea

Oliga [24]

I believe it should be .3 because its rounded to the nearest tenth

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2 years ago

-8 x+3=-29 what is x?

kykrilka [37]

Answer:

x=4

Step-by-step explanation:

To solve for x, use inverse operations:

-8x+3 = -29 Subtract 3 from both sides

-8x +3 -3 = -29 -3

-8x = -32 Divide both sides by -8

x = 4

3 0

3 years ago

Rewrite the equation in slope-intercept form. x=4y+2

Dafna1 [17]

Answer:

y = x/4 - 1/2

Step-by-step explanation:

Slope-Intercept Form: y = mx + b

Step 1: Write equation

x = 4y + 2

Step 2: Subtract 2 on both sides

x - 2 = 4y

Step 3: Divide both sides by 4

x/4 - 1/2 = y

7 0

3 years ago

Read 2 more answers

Whicl ordered pair makes the inequality true? X+y>8

r-ruslan [8.4K]

Some ordered pairs are:(10,5), (0,9), and (3,15) that make the equation true.
Hope this helps!! ::))
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4 0

3 years ago

Please help I am so lost!!!

ASHA 777 [7]

$\bf tan\left( \frac{x}{2} \right)+\cfrac{1}{tan\left( \frac{x}{2} \right)}\\\\
-----------------------------\\\\
tan\left(\cfrac{{{ \theta}}}{2}\right)=
\begin{cases}
\pm \sqrt{\cfrac{1-cos({{ \theta}})}{1+cos({{ \theta}})}}
\\ \quad \\

\cfrac{sin({{ \theta}})}{1+cos({{ \theta}})}
\\ \quad \\

\boxed{\cfrac{1-cos({{ \theta}})}{sin({{ \theta}})}}
\end{cases}\\\\$

$\bf -----------------------------\\\\
\cfrac{1-cos(x)}{sin(x)}+\cfrac{1}{\frac{1-cos(x)}{sin(x)}}\implies \cfrac{1-cos(x)}{sin(x)}+\cfrac{sin(x)}{1-cos(x)}
\\\\\\
\cfrac{[1-cos(x)]^2+sin^2(x)}{sin(x)[1-cos(x)]}\implies 
\cfrac{1-2cos(x)+\boxed{cos^2(x)+sin^2(x)}}{sin(x)[1-cos(x)]}
\\\\\\
\cfrac{1-2cos(x)+\boxed{1}}{sin(x)[1-cos(x)]}\implies \cfrac{2-2cos(x)}{sin(x)[1-cos(x)]}
\\\\\\
\cfrac{2[1-cos(x)]}{sin(x)[1-cos(x)]}\implies \cfrac{2}{sin(x)}\implies 2\cdot \cfrac{1}{sin(x)}\implies 2csc(x)$

4 0

3 years ago