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Anit [1.1K]
3 years ago
9

" class="latex-formula">
​
Mathematics
2 answers:
stiks02 [169]3 years ago
8 0
Around 2.83

if they want you to do it in square root form then leave as is because it cannot be simplified more.
g100num [7]3 years ago
7 0
Answer:

2.828427125

Step-By-Step Explanation:
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When you flip a biased coin the probability of getting a tail is 0.34. Find the probability of getting a head.
koban [17]

Answer:

If you want to know what the probability is to get at least one Heads, then that is the same as the probability of all the events (100%, or 1) minus the probability of getting all Tails.

There are 100 coins. 99 are fair, 1 is biased with both sides as heads. With a fair coin, the probability of three heads is 0.53=1/8. The probability of picking the biased coin: P(biased coin)=1/100.

Step-by-step explanation:

5 0
3 years ago
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Х- 1, 2, 3 ,4
Len [333]
I think it’s C, good luck
4 0
3 years ago
Analyze a graph In Exercise,analyze and sketch the graph of the function.Label any relative extrema, points of inflation,and asy
FinnZ [79.3K]

Answer:

Step-by-step explanation:

Given is a function of x

f(x) = xe^{-x}

When y=0 we get x=0 and infinity

Hence x intercept is 0 and one asymptote is x axis.

When x=0 , y =0

f'(x) = e^{-x}(-x+1)

f''(x) = e^{-x}(x-1-1)

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Increasing upto x=1 and then decreases

Graph is enclosed

6 0
3 years ago
Is the number 17 a prime or composite number?
Alborosie

Answer:

It is a prime number.

Step-by-step explanation:

A prime number is a number that can only be the product of 1 and itself. 17 can only be multiplied by 1 and 17, so it is prime.

7 0
3 years ago
Tan9°. tan27°. tan45°. tan72°. tan81°= 1​<br><br>could u plz solve it with clear process
Inga [223]

<u>Correct</u><u> </u><u>question</u><u>:</u><u>-</u>

<u>Prove </u><u>that </u><u>tan9.</u><u>t</u><u>a</u><u>n</u><u>1</u><u>7</u><u>.</u><u>t</u><u>a</u><u>n</u><u>4</u><u>5</u><u>.</u><u>t</u><u>a</u><u>n</u><u>7</u><u>3</u><u>.</u><u>t</u><u>a</u><u>n</u><u>8</u><u>1</u><u>=</u><u>1</u>

<u>LHS</u>

\\ \sf\longmapsto tan9.tan17.tan45.tan73.tan81

\\ \sf\longmapsto tan9.tan81.tan17.tan73.tan45

\\ \sf\longmapsto tan(90-81).tan81.tan(90-73).tan73.1

\\ \sf\longmapsto cot81.tan81.cot73.tan73

\\ \sf\longmapsto 1.1

\\ \sf\longmapsto 1

5 0
2 years ago
Read 2 more answers
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