Answer:

Step-by-step explanation:





Pieces of yarn .... 1/8 yard long (each)
a piece of yarn ... n = 3 yards long
remaining ... 1 1/4 yards = 5/4 yards
If you would like to calculate how many 1/8 yard pieces can Sarah cut and still have 1 1/4 yards left, you can do this using the following steps:
n - 1 1/4 = <span>3 - 1 1/4 </span>= 3 - 5/4 = 12/4 - 5/4 = 7/4 = 1 3/4 yards
7/4 / 1/8 = 7/4 * 8/1 = 14 pieces
Result: Sarah can cut 14 1/8 yard pieces and still have 1 1/4 yards left.
Answer:
198 cubic metres
Steps:
<em><u>Find </u></em><em><u>the </u></em><em><u>area </u></em><em><u>of </u></em><em><u> </u></em><em><u>cross</u></em><em><u> </u></em><em><u>section</u></em>
<em><u>Area </u></em><em><u>if </u></em><em><u>traing</u></em><em><u>l</u></em><em><u>e </u></em><em><u>+</u></em><em><u> </u></em><em><u>Area </u></em><em><u>of </u></em><em><u>square</u></em>
<em><u>1</u></em><em><u>/</u></em><em><u>2</u></em><em><u> </u></em><em><u>×</u></em><em><u> </u></em><em><u>3</u></em><em><u> </u></em><em><u>×</u></em><em><u> </u></em><em><u>4</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>4</u></em><em><u>×</u></em><em><u>4</u></em>
<em><u>6</u></em><em><u>+</u></em><em><u> </u></em><em><u>1</u></em><em><u>6</u></em>
<em><u>2</u></em><em><u>2</u></em>
<em><u>Then </u></em><em><u>times </u></em><em><u>with </u></em><em><u>the </u></em><em><u>lenght </u></em><em><u>(</u></em><em><u>9</u></em><em><u>)</u></em>
<em><u>2</u></em><em><u>2</u></em><em><u>×</u></em><em><u>9</u></em>
I hope this helps, dont hesitate to ask for any question.
Mark me as brainliest is appreciated.Tq!!
Answer:
None of the above.
Step-by-step explanation:
It is neither equiangular nor equilateral because we are given no indication of the sides and angles and it cannot be regular since it is neither equiangular nor equilateral. Therefore, the answer is none of the above.
Answer:
24
Step-by-step explanation:
4 x 3 = 12
12 x 2= 24
Coefficient is the number infront of the varible being multiplied. In this case 24 is the coefficient, and Q is the variable.