Answer:
1448 mL
Step-by-step explanation:
The mass is the same.
Formula
m = d*V
Givens
<em><u>Olive Oil</u></em>
d = 0.92 grams / mL
V = ??
<em><u>Gasoline</u></em>
d = 0.74 grams / mL
V = 1.8 L = 1.8 L * (1000 ml / L)
V = 1800 mL
Solution
0.74 * 1800 mL = 0.92 * x Divide both sides by 0.92
0.74/0.92 * 1800 mL = 0.92 *x / 0.92 Combine the left
0.8043 * 1800 mL = x
x = 1448 mL
The volume of Olive Oil needed is 1448 mL
Answer:
t=0 Sugar = 0 Kg
t=1min Sugar=0.27 Kg
Step-by-step explanation:
Data
Tank = 2640 L (pure water)
Sol=0.09kg Sugar per liter
Vin = Vout = 3L/min
Sugar in the beginning = ?
if beginning is t = 0min Amount of sugar = 0, this is due to the fact that at the moment of entering the tank the content is only water
, but if beginning is t= 1min then;

Answer:
x = 31.4
PQ = 58.8
Step-by-step explanation:
Set up a proportion:
SQ/QP = ST/PR
Substitute in the values they give you:



This means that PQ = 2x - 4 = 2(31.4) - 4 = 62.8-4 = 58.8