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Alika [10]
3 years ago
8

Consider function h. Complete the statements describing the y-values of function h.

Mathematics
1 answer:
dsp733 years ago
8 0

Answer:

1) <em>The end behavior of function </em>h<em> is described by an absolute (horizontal) asymptote.</em>

2) <em>The range of function </em>h<em> is all y-values less than or equal to 0 and greater than 1. </em>

Step-by-step explanation:

1) The end behavior of the function is defined by a horizontal asymptote, that is the values of y when x tends to \pm \infty. Answer: <em>The end behavior of function </em>h<em> is described by an absolute (horizontal) asymptote.</em>

2) The range of the function is the set of values of y associated with the function. The existence of two vertical asymptotes give the following solution for the range: Ran \{h\} = (-\infty, 0] \,\cup\,(1, +\infty) Answer: <em>The range of function </em>h<em> is all y-values less than or equal to 0 and greater than 1. </em>

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How many milliliters of olive oil (D=0.92 g/mL) have the same mass as 1.80 L of gasoline (D= .74 g/mL)
True [87]

Answer:

1448 mL

Step-by-step explanation:

The mass is the same.

Formula

m = d*V

Givens

<em><u>Olive Oil</u></em>

d = 0.92 grams / mL

V = ??

<em><u>Gasoline</u></em>

d = 0.74 grams / mL

V = 1.8 L = 1.8 L * (1000 ml / L)

V = 1800 mL

Solution

0.74 * 1800 mL = 0.92 * x                      Divide both sides by 0.92

0.74/0.92 * 1800 mL = 0.92 *x / 0.92   Combine the left

0.8043  * 1800 mL = x

x = 1448 mL

The volume of Olive Oil needed is 1448 mL

   


5 0
3 years ago
A recipe calls for 3/4 cups of flour . Estevan wants to make 1/3 of the recipe how much flour will he need
romanna [79]
1/3 × 3/4 = 1/4 :) hope this helped!
7 0
4 years ago
Read 2 more answers
The eatery restaurant has 200 tables. On a recent evening there were reservations for 1/10 of the tables. How many tables were r
lbvjy [14]
20 the answer for this is 20
3 0
3 years ago
(1 point) A tank contains 2640 L of pure water. A solution that contains 0.09 kg of sugar per liter enters the tank at the rate
OverLord2011 [107]

Answer:

t=0      Sugar = 0 Kg

t=1min Sugar=0.27 Kg

Step-by-step explanation:

Data

Tank = 2640 L (pure water)

Sol=0.09kg Sugar per liter

Vin = Vout = 3L/min

Sugar in the beginning = ?

if beginning is t = 0min Amount of sugar = 0, this is due to the fact that at the moment of entering the tank the content is only water , but if beginning is t= 1min then;

\frac{3L}{min}*\frac{0.09Kg}{L}=0.27kg/min

7 0
3 years ago
Read 2 more answers
If triangle PQR is similar to SQT, find the value of
ankoles [38]

Answer:

x = 31.4

PQ = 58.8

Step-by-step explanation:

Set up a proportion:

SQ/QP = ST/PR

Substitute in the values they give you:

\frac{x-9}{x-9+x+5}  = \frac{8}{21}

\frac{x - 9}{2x - 4} = \frac{8}{21}

21x - 189 = 16x - 32\\5x = 157\\x = 31.4

This means that PQ = 2x - 4 = 2(31.4) - 4 = 62.8-4 = 58.8

5 0
3 years ago
Read 2 more answers
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