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o-na [289]
3 years ago
13

3. Tamu has 17 cards. Richard gives her t cards. Tamu now has at least 38 cards. Which best describes Tamu’s cards? *

Mathematics
1 answer:
Shkiper50 [21]3 years ago
6 0
I believe the answer is B
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I NEED HELP plz i will pay u 15 points if u help meeee
Arlecino [84]

Answer:

1. 9/10  

2. 14/15

3. 1   1 /6 or 7/6

Step-by-step explanation:

1. Change the 5, the denominator to 10.  8/10

then add to 1/10  8/10 + 1/10= 9/10

2. Change both denimnators to 15. You will then get 9/15 and 5/15.

Add them together and get 14/15

3. Change both denominators to 6 and you will get 3/6 and 4/6.

Add them together to get 7/6.

If you want to make it into a mixed fraction it would be 1 1/6 (as in one and one-sixth)

8 0
2 years ago
Read 2 more answers
Working a second job _____.
hram777 [196]
I believe it would be all of the above let me know if it is right
7 0
3 years ago
I need help with the 3rd one if appreciate it.
igor_vitrenko [27]

Answer:

skp

Step-by-step explanation:

5 0
2 years ago
I can’t figure out how to use the zeros in the polynomial. Please explain
Temka [501]

Answer:

a) P (x) = (x + 3) (x-1) (x-4)

b) P (x) = (2x + 5) (5x - 4) (x-6)

c) P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2

Step-by-step explanation:

<u>For the question a *</u> you need to find a polynomial of degree 3 with zeros in -3, 1 and 4.

This means that the polynomial P(x) must be zero when x = -3, x = 1 and x = 4.

Then write the polynomial in factored form.

P (x) = (x + 3) (x-1) (x-4)

Note that this polynomial has degree 3 and is zero at x = -3, x = 1 and x = 4.

<u>For question b, do the same procedure</u>.

Degree: 3

Zeros: -5/2, 4/5, 6.

The factors are

x = -\frac{5}{2}\\\\x +\frac{5}{2} = 0\\\\(2x +5) = 0

---------------------------------------

x =\frac{4}{5}\\\\x-\frac{4}{5} = 0\\\\(5x-4) = 0

--------------------------------------

x = 6\\\\(x-6) = 0

--------------------------------------

P (x) = (2x + 5) (5x - 4) (x-6)

<u>Finally for the question c we have</u>

Degree: 5

Zeros: -3, 1, 4, -1

Multiplicity 2 in -1

x = -3\\\\(x-3) = 0

--------------------------------------

x = 1\\\\(x-1) = 0

--------------------------------------

x = 4\\\\(x-4) = 0

----------------------------------------

x = -1\\\\(x + 1) = 0

-----------------------------------------

P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2

8 0
3 years ago
THIS IS A QUESTION FROM MY FINAL EXAM PLEASE HELP
snow_lady [41]

Answer:

0.44

Step-by-step explanation:

4 0
2 years ago
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