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hram777 [196]
3 years ago
14

Find the period of an electromagnetic wave of wavelength 2.20 × 10–2 m. A. 1.36 × 1010 s c. 7.33 × 10–11 s b. 4.54 × 101 s d. 6.

60 × 106 s
Mathematics
1 answer:
vovangra [49]3 years ago
4 0

Answer:

7.33 * 10^-11 s

Step-by-step explanation:

Period, T = 1 / f

c = fλ

λ = 2.20 × 10^–2 m

c = speed of light = 3 * 10^8 m

f = c / λ

f = 3 * 10^8 ÷ 2.20 × 10^–2 m

f = (3/2.2) * 10^(8-(-2))

f = 1.364 * 10^10

T = 1/f

T = 1 / 1.364 * 10^10

T = 7.33 * 10^-11 s

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Step-by-step explanation:

1) -22

2) -172.368

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Math: Just Sip Awhile Cafe has several pastries for sale.
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2 years ago
3(x + 1) = -2 (x - 1) -4
AlekseyPX

Answer:

x = -1

Step-by-step explanation:

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3 years ago
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I really need help <br> it’s very hard
barxatty [35]

Answer:

The angle ZLK has a value of 75 degrees.

Step-by-step explanation:

We can calculate this as:

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6 0
3 years ago
Find the cosine of each acute angle
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Answer:

cos P = 53 degrees

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Step-by-step explanation:

cos P = \frac{adjacent}{hypothenuse}

cos P = \frac{24}{40}

cos P = 0.60

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cos Q = 37 degrees

To check anser:

90 + 53 + 37 = 180

180 = 180

4 0
3 years ago
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